Question

What is the area of a 45 degree sector of a circle with a radius of 12 in.

Answer 1

given ,

a circle of radius 12 inches

and $\theta$ = 45°

now we know that ,

$\\{Area \: of \: sector = \frac{\theta}{360\degree} \times \pi \: r {}^{2} }$

let's now plug in the values of radius and theta as 12 inches and 45° respectively ,

$\\\dashrightarrow \: \frac{45}{360} \times \frac{22}{7} \times 12 \times 12 \\ \\ \dashrightarrow \: \frac{1}{8} \times \frac{22 \times 12 \times 12}{7} \\ \\ \dashrightarrow \: \frac{22 \times 12 \times 12}{56} \\ \\ \dashrightarrow \: \frac{3168}{56} \\ \\ \dashrightarrow \: 56.57 \: inches {}^{2} (approx.)$

hope helpful :D