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Finger [1]
3 years ago
11

What is the equation of the quadratic graph with a focus of (8, −8) and a directrix of y = −6?

Mathematics
1 answer:
yarga [219]3 years ago
4 0
The vertex is exactly half way between directrix and focus. In this case the vertex is (8,-7)
               (h,k)

P is the distance between the vertex and either the directrix or focus,  in this case p = 1. 

a = 1/(4p)  or 1/(4*1) or 1/4

write the equation in vertex form

y = a(x-h)^2 + k

y = 1/4(x-8)^2 -7
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Ne4ueva [31]

Answer:

Option B can be quadratic.

Step-by-step explanation:

Take a look at the data.

A quadratic equation is of the form ,

y = ax^{2} +bx + c,

where, a,b,c are constants.

<em>To find an unknown equation of 3 variables,</em>

<em>we need 3 points lying on the equation.</em>

here they have given, 5 points, meaning all should lie on the curve.

<em>For first option,</em> inserting first 3 points to find equation, we get equation as,

y = x^{2} -4x +11, but the rest points don't satisfy the curve.

So first option is not quadratic.

Similarly, it can be shown that option C and D are also not quadratic.

While, in option B, it is clear that for every y, x is y squared,

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6 0
3 years ago
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tiny-mole [99]

Answer:

You can use Gaussian Elimination.

Double both sides of the first equation and add the second equation.

6x + 4y = 8

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x = 1

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Step-by-step explanation:

7 0
3 years ago
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telo118 [61]

Answer: please find the attached files

Step-by-step explanation:

A unit circle formula and special triangle of 45, 30 and 60 degrees can be used to solve the problem.

Please find the attached files for the solution

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olasank [31]

Answer: (x+y)-6

Step-by-step explanation:

i think lol

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