What is the equation of the quadratic graph with a focus of (8, −8) and a directrix of y = −6?

1 answer:

4 0

The vertex is exactly half way between directrix and focus. In this case the vertex is (8,-7)
(h,k)

P is the distance between the vertex and either the directrix or focus, in this case p = 1.

a = 1/(4p) or 1/(4*1) or 1/4

write the equation in vertex form

y = a(x-h)^2 + k

y = 1/4(x-8)^2 -7

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vladimir1956 [14]

This is what you would do
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= 0 to the nearest tenth

= 0 to the nearest hundredth

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Anon25 [30]

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3 years ago

Perform the indicated operation. 15b/4 * 8/9a^2b^2

Sergio [31]

Answer:

The simplified expression is $\frac{10}{3 a^2 b}$

Step-by-step explanation:

The given expression is:

$\frac{15b}{4} * \frac{8}{9a^2 b^2}$

Multiply the items in the numerator together ( 15b * 8 = 120 b). Also multiply the items in the denominator together ( 4 * 9a²b² = 36a²b²). The expression thus becomes:

$= \frac{120b}{36 a^2 b^2} \\\\$