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expeople1 [14]
3 years ago
15

Find the x intercept(s) y= -x^2 + 2

Mathematics
2 answers:
VashaNatasha [74]3 years ago
4 0

Answer:

(\pm \sqrt{2}, 0)

Step-by-step explanation:

The x intercepts are basically the points at which y = 0.

-x^2 + 2 = 0

-x^2 = -2

x^2 = 2

x = \pm \sqrt{2}

yuradex [85]3 years ago
3 0

For this case we have by definition, that to find the x-intercept points, we must make the variable y = 0 and clear the value of "x". So:

y = -x ^ 2 + 2\\0 = -x ^ 2 + 2\\x ^ 2 = 2\\x = \sqrt {2}

So, the x-intercepts are:

(x_ {1}, y_ {1}) = (\sqrt {2}, 0)\\(x_ {2}, y_ {2}) = (- \sqrt {2}, 0)

ANswer:

(x_ {1}, y_ {1}) = (\sqrt {2}, 0)\\(x_ {2}, y_ {2}) = (- \sqrt {2}, 0)

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