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STALIN [3.7K]
3 years ago
14

Samantha is making special edition hazelnut and almond chocolate boxes to give to her friends. It costs Samantha $15 to make one

hazelnut chocolate box and $30 to make one almond chocolate box. It takes her 20 minutes to make either box of chocolates. She wants to spend no more than $210 and 200 minutes making the chocolate boxes to give to her friends.
Mathematics
2 answers:
Slav-nsk [51]3 years ago
7 0

Answer:

Samantha should make six hazelnut chocolate boxes and four almond chocolate boxes in order to maximize the number of chocolates she gives to her friends.

Step-by-step explanation: This is the right answer

Harrizon [31]3 years ago
5 0

Answer:

6 hazelnut

4 almond

Step-by-step explanation:

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Multiply.
Nady [450]

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Explanation:</h2>

Here we have the following expression:

3\sqrt{22}\sqrt{58}\sqrt{18}

So we need to simplify that radical expression. By property of radicals we know that:

\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}

So:

3\sqrt{22}\sqrt{58}\sqrt{18}=3\sqrt{22\times 58 \times 18}=3\sqrt{22968}

The prime factorization of 22968 is:

22968=2^3\cdot 3^2\cdot11\cdot 29

Hence:

3\sqrt{22968}=3\sqrt{2^3\cdot 3^2\cdot11\cdot 29}=3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29}

By property:

\sqrt[n]{a^n}=a

So:

3\sqrt{2^2\cdot 3^2\cdot 2\cdot 11\cdot 29} \\ \\ 3(2)(3)\sqrt{2\cdot 11\cdot 29}=18\sqrt{638}

Finally:

\boxed{3\sqrt{22}\sqrt{58}\sqrt{18}=18\sqrt{638}}

<h2>Learn more:</h2>

Radical expressions: brainly.com/question/13452541

#LearnWithBrainly

3 0
3 years ago
Definition: The ___ of an event happening is expressed as a fraction between 0 and 1.
aliina [53]

Definition: The <u>probability</u> of an event happening is expressed as a fraction between 0 and 1.

Example: The <u>chance</u> that you roll a 4 on a die is 1

3 0
4 years ago
The point (5/13,y) in the fourth quadrant corresponds to angle θ on the unit circle.
andreyandreev [35.5K]
Cos θ = adjacent / hypothenus = 5/13
opposite = sqrt(hypothenus^2 - adjacent^2) = sqrt(13^2 - 5^2) = sqrt(169 - 25) = sqrt(144) = 12

sec θ = 1/cos θ = 1/(adjacent / hypothenus) = hypothenus / adjacent = 13/5
cot θ = 1/tan θ = 1/(opposite/adjacent) = adjacent / opposite = 5/12

sec θ = 13/5
cot θ = 5/12
5 0
4 years ago
Can someone help me solve A-D? I have answers in the back of the book, but I can't figure out how they (they being the author of
Ivan
Alright. So for:
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**If you don't understand distributing, just let me know!
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Ira Lisetskai [31]

There was no temperature change. Simple, easy math.

The POPULATION increased by 22000

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