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3 years ago

Definition: The ___ of an event happening is expressed as a fraction between 0 and 1.

Mathematics

1 answer:

aliina [53]3 years ago

3 0

Definition: The <u>probability</u> of an event happening is expressed as a fraction between 0 and 1.

Example: The <u>chance</u> that you roll a 4 on a die is 1

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Given the function f(x) = 4x^2 - 17, find f (h+2).

forsale [732]

Answer:

Step-by-step explanation:

Substitute x = h + 2 into f(x), that is

f(h + 2)

= 4(h + 2)² - 17 ← expand factor using FOIL

= 4(h² + 4h + 4) - 17 ← distribute parenthesis and simplify

= 4h² + 16h + 16 - 17

= 4h² + 16h - 1 → B

6 0

2 years ago

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Can a zero slope be a function

steposvetlana [31]

Answer:

A zero slope means there is no change in the y -coordinates as the x -coordinates change, so this is a horizontal line.

Step-by-step explanation:

pls give brainliest

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3 years ago

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A graphic charges a fee of 1600 to design a poster for a jazz festival the designer also receives 8% commission on sales of the

iris [78.8K]

Answer:

The total income of designer from this work is $1649.6.

Step-by-step explanation:

The fees charged by the designer = $1600

The commission on total sales = 8%

Total sales amount in the festival = $620

Now, 8% of $620 = $\frac{8}{100} \times 620 = 49.6$

So, the commission on total sales = $49.6

Also, Total Income of the designer = Deign Fee + 8% Commission fee

= $1600 + $49.6

= $1649.6

Hence, the total income of designer from this work is $1649.6.

5 0

3 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

Leni [432]

Answer: $\dfrac{2x^2-1}{x(x^2-1)}$

Step-by-step explanation:

The given function : $y=\ln(x(x^2 - 1)^{\frac{1}{2}})$

$\Rightarrow\ y=\ln x+\ln (x^2-1)^{\frac{1}{2}}$ [ $\because \ln(ab)=\ln a +\ln b$ ]

$\Rightarrow y=\ln x+\dfrac{1}{2}\ln (x^2-1)}$ [ $\because \ln(a)^n=n\ln a$ ]

Now , Differentiate both sides with respect to x , we will get

$\dfrac{dy}{dx}=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})\dfrac{d}{dx}(x^2-1)$ (By Chain rule)

[Note : $\dfrac{d}{dx}(\ln x)=\dfrac{1}{x}$ ]

$\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x-0)$

[ $\because \dfrac{d}{dx}(x^n)=nx^{n-1}$ ]

$=\dfrac{1}{x}+\dfrac{1}{2}(\dfrac{1}{x^2-1})(2x) = \dfrac{1}{x}+\dfrac{x}{x^2-1}\\\\\\=\dfrac{(x^2-1)+(x^2)}{x(x^2-1)}\\\\\\=\dfrac{2x^2-1}{x(x^2-1)}$

Hence, the derivative of the given function is $\dfrac{2x^2-1}{x(x^2-1)}$ .

8 0

3 years ago

Explain how to write the number that is 0.02 less than 1.423

Katyanochek1 [597]

Less than means subtract. So, 0.02 less than 1.423 is 1.423 - 0.02 which equals >>> 1.403

6 0

2 years ago