The x-axis intercepts are the roots of the polynomial. So, the roots are x = - 2, x = - 1 and x = 3.

Therefore, the polynomial can be factored as:

(x - (-2)) * ( x - (-1) ) * (x - 3) = (x + 2)(x + 1)(x - 3).

Answer: (x + 2) (x + 1) (x - 3)

5 0

3 years ago

4th grade math question Joey walk 333 ft how many yards did Joey walk? At 5 yds vs 15 ft

icang [17]

111 yards

Explanation

Step 1

to solve this we need to know the equivalence

$\begin{gathered} 3\text{ ft= 1 yd} \\ 3\text{ ft}\leftrightarrow1\text{ yd} \end{gathered}$

Now, we can apply a rule of three

let x represents the number of yards in 333 ft, so

$\begin{gathered} if \\ 3\text{ ft}\rightarrow\text{ 1 yd} \\ \text{then} \\ 33\text{ ft}\rightarrow x \end{gathered}$

as the ratio is the same, we have a proportion

$\begin{gathered} \frac{3\text{ ft}}{1\text{ yd}}=\frac{33\text{ ft}}{x\text{ yd}} \\ \frac{3}{1}=\frac{33}{x} \end{gathered}$

Step 2

now, solve for x

$\begin{gathered} \frac{3}{1}=\frac{333}{x} \\ \text{cross multiply} \\ 3\cdot x=333\cdot1 \\ 3x=333 \\ \text{divide both } \\ \frac{3x}{3}=\frac{333}{3} \\ x=111 \end{gathered}$

so, the answer is 111 yards

I hope this helps you

8 0

1 year ago

In quadrilateral ABCD, BN and DM are drawn perpendicular to AC such that BN = DM. Prove that O is the midpoint of BD

GaryK [48]

Answer:

Step-by-step explanation:

Given :

In the given quadrilateral ABCD,

BN and DM are the perpendiculars drawn to AC such that,

BN = DM

To prove:

Point O is the midpoint of segment BD.

OD = OB

Solution:

In ΔOMD and ΔONB,

∠MOD ≅ NOB [Vertical angles]

∠M ≅ ∠N ≅ 90° [Given]

Therefore, by AA property of similarity,

ΔOMD ~ Δ ONB

Therefore, their corresponding sides will be proportional,

$\frac{DM}{BN}=\frac{OD}{OB}$

Since BN = DM,

OD = OB

Hence O is the midpoint of BD.

4 0

4 years ago