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Art [367]
3 years ago
8

Write 5^4 in standard form

Mathematics
2 answers:
salantis [7]3 years ago
5 0

Answer:

Step-by-step explanation:

5x5x5x5 = 625

x = times

AfilCa [17]3 years ago
4 0

Answer:

625

600+20+5

Step-by-step explanation:

<em>Parenthesis</em>

<em>Exponent</em>

<em>Multiply</em>

<em>Divide</em>

<em>Add</em>

<em>Subtract</em>

<em>From left to right.</em>

<em>Do exponent first.</em>

<em>5^4=5*5*5*5=625</em>

<em>Standard form of 5^4 is: ⇒  600+200+5</em>

<em>625 is the correct answer.</em>

<em>600+200+5 is the correct answer.</em>

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eduard
The answer is 3.7a+3b

Because you combine like terms
3 0
2 years ago
Read 2 more answers
Sean went to the farmers Market and bought 3 3/4 pounds of beans at $11 and a pound and 10 1/2 pounds of flour at $0.55 per poun
mina [271]
11 x 3 3/4 = 41 1/4 (41.25)

10 1/2 x 0.55 = 5.775

41.25 + 5.775 = 47.025

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Hope it helps!
4 0
3 years ago
One hundred eighty is equal to how many tens
Nadya [2.5K]
There are 18 tens in 180 because if you divide 180 divided by 10, you get 18. you can also do it in your head!!! 
Hope this helps!!!
5 0
3 years ago
Hello! Can you please help me on these two problems? =)
poizon [28]

Yeah, I gotta read the questions better.

Perimeter not area.

diagonal length = √((28 - 12)² + (24 - 10)²) = 21.26

P = 12 + 10 + 28 + 24 + 21.26 = 95.26 units

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R = √(379.94 / 4(3.14) = 5.5 in

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4 0
3 years ago
For the region bounded by y=2x​, the​ x-axis, and x=1​, determine which of the following is​ greater: the volume of the solid ge
telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

\int\limits^1_0 {(pi)y^{2} } \, dx

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0
2 years ago
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