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Art [367]
3 years ago
8

Write 5^4 in standard form

Mathematics
2 answers:
salantis [7]3 years ago
5 0

Answer:

Step-by-step explanation:

5x5x5x5 = 625

x = times

AfilCa [17]3 years ago
4 0

Answer:

625

600+20+5

Step-by-step explanation:

<em>Parenthesis</em>

<em>Exponent</em>

<em>Multiply</em>

<em>Divide</em>

<em>Add</em>

<em>Subtract</em>

<em>From left to right.</em>

<em>Do exponent first.</em>

<em>5^4=5*5*5*5=625</em>

<em>Standard form of 5^4 is: ⇒  600+200+5</em>

<em>625 is the correct answer.</em>

<em>600+200+5 is the correct answer.</em>

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pls help me literally pls help me i need this done before tmr ad i have alot more to do pls help thanks
julsineya [31]

Answer:

y = −3x+7

Step-by-step explanation:

m = slope

slope = change in y / change in x

slope = ▲y/▲x

slope = -3 / 1

slope = -3

y-intersect = (0,7)

The slope-intercept form of linear equation:-  

y = mx + b

where:

m = the slope

b = y-intersect

*we plot the information we have get in the formula

y = mx + b

y = -3x + 7

*and this is the equation of the graph

8 0
3 years ago
Select the outlier in the data set.
Katarina [22]

Answer:

86

Step-by-step explanation:

21   <u>3</u>6

<em>5</em>2   <em>4</em>0

<u>3</u>2   <em><u>86</u></em>

<u>3</u>3   <u>3</u>8

28   <u>3</u>4

<u>3</u>0   <em>1</em>9

6 0
2 years ago
Answer the question in the picture
nekit [7.7K]

Recall the angle sum identities:

\sin(x+y)=\sin x\cos y+\cos x\sin y

\cos(x+y)=\cos x\cos y-\sin x\sin y

Now,

\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}

Divide through numerator and denominator by \cos x\cos y to get

\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}

Next, we use the fact that x,y lie in the first quadrant to determine that

\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2

\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}

So we then have

\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1

Finally,

\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73

4 0
3 years ago
Do you solve math in parentheses last or first​
Flura [38]

It has to be solved first.

Step-by-step explanation:

  • Parentheses has to be solved first according to the BODMAS Principle which is Brackets Open Division Multiplication Addition and Subtraction
  • If this is not followed, the answers will be different and will not get the right answer.
  • It is the same as PEDMAS which is Parenthesis Exponents Division Multiplication Addition and Subtraction
8 0
3 years ago
A football team earns 6 points for a touchdown and 3 points for a field goal. In one game, a team scored a touchdown and some fi
Alja [10]

Answer:

6+3(f)=18

6+3f=18

3f=12

f=4

Step-by-step explanation:

3 0
2 years ago
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