Basically, you just want to keep flipping a coin a total of 10 times, 27 more times. (If that makes any sense) You also want to keep recording the number of heads in each set of 10.
Let L be the length
Let w be the width
Let p be the perimeter
L+w+L+w=p
L=w+20
3L+2w+3L+2w=240
Sub the first equation in for L in the second equation and solve for w
3(w+20)+2w+3(w+20)+2w=240
3w+60+2w+3w+60+2w=240
10w+120=240
10w=240-120
10w=120
W=120/10
W=12
Sub w into the first equation and solve for L
L=w+20
L=12+20
L=32
Hope this helps!
Answer:
They are adding 16 to the number each time. So the next number in the sequence would be 78.
Step-by-step explanation:
d(1) = 14
d(n) = d (n-1) + 16
14 + 16 = 30
30 + 16 = 46
46 + 16 = 62
62 + 16 = 78 and so on...
The probability that 5 would not be working is 0.18665, the probability that at least one machine would be working is 0.00602 and the probability that all would be working is 1.
Given a company has 200 machines. Each machine has a 12% probability of not working.
If we working pick 40 machines randomly then we have to find the probability that 5 would not be working, the probability that at least one machine would be working, and the probability that all would be working.
So
1) probability that 5 would not be working
C(40,5)·0.12⁵·0.88³⁵= 40!/(5!(40-5)!)·0.12⁵·0.88³⁵
≈ 0.18665
2) probability that at least one machine would be working
0.88⁴⁰ ≈ 0.00602
3) probability that all would be working
1 - 0.12⁴⁰ ≈ 1.0000
Learn more about probability here: brainly.com/question/24756209
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Given that,
velocity, v = 7.8 ft/s
Radius, r = 1.25 ft
To find,
a. What is the acceleration of the bucket?
b. What is the velocity if the acceleration is 25 ft/sec²?
Solution,
(a) The centripetal acceleration is given by :
Put v = 7.8 ft/s and r = 1.25 ft
(b) Put a = 25 ft/s² to find velocity.
Hence, this is the required solution.
