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SpyIntel [72]
2 years ago
7

Dave found that about 8/9 of the students in his class have a cell phone.What percent of the students in his class do NOT HAVE a

cell phone
Mathematics
1 answer:
iris [78.8K]2 years ago
6 0
If the number of students in the class is considered to be 1, and 8/9 of the students have a cell phone, the fraction indicating the number of students who do not have a cell phone is:
1- 8/9= 1/9.

1/9 of the students don't have a cell phone~
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Perform the following computations.You may use13≈0.333333,34= 0.75 and100301= 0.332226.(i). Compute13+34by using five significan
White raven [17]

Answer:

a. 1.0833

Absolute Error = 0.416667

Relative Error = 1.250002

b. 0.0011070

Absolute Error = 0.0011070

Relative Error = 0.003321

Step-by-step explanation:

Given

1/3 = 0.333333

3/4 = 0.75

100/301 = 0.332226

a.

1/3 + 3/4

= 0.333333 + 0.75

= 1.083333

= 1.0833 ------ Approximated to 5 significant digits

Absolute Error = |Real Value - Estimated Value|

Relative Error = Absolute Error/Real Value

Assume 1/3 to be the real value and 3/4 to be the estimated value

Absolute Error = |0.333333 - 0.75|

Absolute Error = |-0.416667|

Absolute Error = 0.416667

Relative Error = 0.416667/0.333333

Relative Error = 1.250002

b.

1/3 - 100/301

= 0.333333 - 0.332226

= 0.001107

= 0.0011070 ----- Approximated to 5 significant digits

Assume 1/3 to be real value and 100/301 to be estimated value

Absolute Error = 0.333333 - 0.332226

Absolute Error = 0.0011070

Relative Error = 0.0011070/0.333333

Relative Error = 0.003321

Absolute and relative errors are approximation errors and they are due to the discrepancy between an exact value and some approximation to them.

The absolute error is the magnitude of the difference between the exact value and the approximation. The relative error is the absolute error divided by the magnitude of the exact value

4 0
3 years ago
Danielle has her finals coming up and she's worried she'll fail her class. Her past 3 test grades were a 72. an 85, and a 68. Sh
natka813 [3]

Answer:

55

Step-by-step explanation:

7 0
2 years ago
Which of the following equations could you solve by first adding six and then dividing by negative three?
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3 years ago
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The height of a triangle is 8 m more than the length of the base. The area of the triangle is 21 m^2. Find the height of the tri
Alexus [3.1K]

Answer:

<h2>height = 12 cm</h2>

Step-by-step explanation:

Area of a triangle is given by

A =  \frac{1}{2} bh

where

b is the base

h is the height

From the question

Area = 21 m²

The statement

The height of a triangle is 8 m more than the length of the base is written as

h = 8 + b

Make b the subject

That's

b = h - 8

Substitute the expression into the above formula and solve for the height

That's

21 =  \frac{1}{2} (h - 8)h

Multiply through by 2

h² - 8h = 48

h² - 8h - 48 = 0

(h + 4)(h - 12) = 0

h + 4 = 0 h - 12 = 0

h = - 4 h = 12

Since the height cannot be a negative number we have the final answer as

<h3>height = 12 cm</h3>

Hope this helps you

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