Answer:
Domain {-2,0,2}
Range {-2,0,2}
Relation is a Function
Step-by-step explanation:
We are given a relation:
{ (-2,-2) , (0,0) , (2,2) }
Domain can be defined as the all possible values of x for a relation. It is considered as a set of all first values of the ordered pairs of a given relation.
Domain of the given relation is {-2,0,2}
Range can be defined as all possible value of y which corresponds to the values of x in the domain. It is considered as a set of all second values of the ordered pairs of a given relation.
Range of the given relation is {-2,0,2}
A relation is a function if only there is one value of y for each value of x. If in the set of ordered pair of the relation, the value of x gets repeated, then the relation is not a function.
As no values of x are getting repeated, the relation is a function.
Answer:
R = (-12, 22)
Step-by-step explanation:
Unfortunately it's not a straight line, so gonna need to put in some extra work. Basically think of it like breaking it into it's horizontal and vertical components then doubling them.
From Q to M you move 10 spaces to the left, so to go from M to R you will go another 10 to the left. Similarly, you start at -10 for the y value and go up 16 to 6, and you will need to go up another 16 to get to R.
So for x, 8 -10 = -2 then -2 - 10 = -12, so R's x value is -12
y we do the same thing. Gonna do it in one step though. -10 + 16 + 16 = 22
So R is (-12, 22)
You will need 6 tennis balls a
Answer:
26/35
Step-by-step explanation:
Each fraction is increasing by 1/35. Therefore, 25/35 + 1/35 = 26/35.
<span>The problem is to calculate the angles of the triangle. However, it is not clear which angle you have to calculate, so we are going to calculate all of them
</span>
we know that
Applying the law of cosines
c²=a²+b²-2*a*b*cos C------> cos C=[a²+b²-c²]/[2*a*b]
a=12.5
b=15
c=11
so
cos C=[a²+b²-c²]/[2*a*b]---> cos C=[12.5²+15²-11²]/[2*12.5*15]
cos C=0.694------------> C=arc cos (0.694)-----> C=46.05°-----> C=46.1°
applying the law of sines calculate angle B
15 sin B=11/sin 46.1-----> 15*sin 46.1=11*sin B----> sin B=15*sin 46.1/11
sin B=15*sin 46.1/11-----> sin B=0.9826----> B=arc sin (0.9826)
B=79.3°
calculate angle A
A+B+C=180------> A=180-B-C-----> A=180-79.3-46.1----> A=54.6°
the angles of the triangle are
A=54.6°
B=79.3°
C=46.1°
