What is the answer?????

HELP ME PLZ!!!!! Plz!!!

Charra [1.4K]

Answer:

hi the right answer is option C.112

here's why:

$\frac{14}{50} \times 400 = 112$

4 0

3 years ago

Sophia has $91,000 in a savings account that earns 7% annually. The interest is not compounded. To the nearest cent, how much wi

USPshnik [31]

Answer:

$95777.5

Step-by-step explanation:

change 7% to decimal = .07

91,000 * .07 = 5370 (annual interest)

5370 / 12 = 530.83 (monthly interest)

530.83 * 9 = 4777.5 (9 months interest)

91,000 + 4777.5 = 95777.5 (initial + 9 months interest)

6 0

3 years ago

The p-value for a one-sided test of the population proportion is 0.0513. Which of

uysha [10]

Using the equation of the test statistic, it is found that with an increased sample size, the test statistic would decrease and the p-value would increase.

<h3>How to find the p-value of a test?</h3>

It depends on the test statistic z, as follows.

For a left-tailed test, it is the area under the normal curve to the left of z, which is the <u>p-value of z</u>.

For a right-tailed test, it is the area under the normal curve to the right of z, which is <u>1 subtracted by the p-value of z</u>.

For a two-tailed test, it is the area under the normal curve to the left of -z combined with the area to the right of z, hence it is <u>2 multiplied by 1 subtracted by the p-value of z</u>.

In all cases, a higher test statistic leads to a lower p-value, and vice-versa.

<h3>What is the equation for the test statistic?</h3>

The equation is given by:

$t = \frac{\overline{X} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{X}$ is the sample mean.

$\mu$ is the tested value.

s is the standard deviation.

n is the sample size.

From this, it is taken that if the sample size was increased with all other parameters remaining the same, the test statistic would decrease, and the p-value would increase.

You can learn more about p-values at brainly.com/question/26454209

3 0

2 years ago

Solve the following ODE's: c) y* - 9y' + 18y = t^2

Nastasia [14]

Answer:

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = $C_1e^{3t}+C_2e^{6t}$

now calculating P.I.

$P.I. = \frac{t^2}{D^2 - 9D +18}$

$P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

hence the complete solution

y = C.F. + P.I.

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

7 0

3 years ago

What is special about one-to-one functions and what types of line tests verify that a function is one-to-one?

snow_tiger [21]

A one to one function is a function where the output is mapped to a unique input.
Horizontal line test is used to check whether a function is one to one.

8 0

3 years ago