A there are no real zeros
using the discriminant b² - 4ac to determine the nature of the zeros
for y = x² + 4x + 5 ( with a = 1, b = 4 and c = 5 )
• If b² - 4ac > 0 there are 2 real and distinct zeros
• If b² - 4ac = 0 there is a real and equal zero
• If b² - 4ac < 0 there are no real zeros
b² - 4ac = 16 - 20 = - 4
Since discriminant < 0 there are no real zeros
Your answer would be y= 6x + 19
You get rid of the variable on the left side by adding it to both sides giving you y = 6x + 19
Hope it helps
