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3 years ago

Please can you please help?!!?!!!!!!??

Mathematics

2 answers:

Novay_Z [31]3 years ago

8 0

That’s not very helpful it’s B

olasank [31]3 years ago

4 0

Answer:

Step-by-step explanation:

im not completely sure but i think it may be c

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A survey was taken of students at Utah High school to see how many students will attend the soccer game tonight. The principal s

makkiz [27]

Answer:

750

Step-by-step explanation:

5 0

3 years ago

PLZ HELP!!! I HAVE AN EXAM!! Find cscΘ if sinΘ=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B-2%7D%7B7%7D" id="TexFormula1" title=

Allisa [31]

$\boxed{\bold{\red{csc\theta=-\frac{7}{2}}}}$

$\large{\red{Solution\: given:}}$

$Sin\theta=\frac{-2}{7}$

we have

$cosec \theta=\frac{1}{Sin\theta} =\frac{1}{\frac{-2}{7}}\\=-\frac{7}{2}$

8 0

3 years ago

Find a 90% confidence interval for the mean of all tree ring dates from this archaeological site. (round your answers to the nea

creativ13 [48]

Given a table below which gives the years in A.D. for an archaeological excavation site using the method of tree ring dating:

$\begin{tabular}
{|c|c|c|c|c|c|c|c|c|}
1229&1292&1187&1257&1268&1316&1275& 1317&1275
\end{tabular}$

Part A:

The sample mean is given by:

$\bar{x}= \frac{1229+1292+1187+1257+1268+1316+1275+ 1317+1275}{9} \\ \\ = \frac{11416}{9} =1268$

Therefore, the sample mean is 1268.

Part B:

We calculate the sample standard deviation as follows:

$s= \frac{1}{9-1} \left(\sqrt{(1229-1268)^2+(1292-1268)^2+(1187-1268)^2+(1257-1268)^2+(1268-1268)^2+(1316-1268)^2+(1275-1268)^2+(1317-1268)^2+(1275-1268)^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{(-39)^2+24^2+(-81)^2+(-11)^2+0^2+48^2+7^2+49^2+7^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{1521+576+6561+121+2304+49+2401+49}\right)\\ \\ = \frac{1}{8}\left(\sqrt{13,582}\right)\\ \\ = \frac{1}{8}(116.54)=14.57\approx15$

Part C:

The 90% confidence interval is given by:

$90\% \ C. \ I.=1268\pm1.65\left(\frac{15}{\sqrt{9}}\right) \\ \\ =1268\pm\left(\frac{15}{3}\right)=1268\pm5 \\ \\ =(1268-5, \ 1268+5)=(1263, \ 1273)$

8 0

3 years ago

Jayden wants to lay sod on his front yard and on half of his back yard. His front yard has a length of 50 feet and a width of 80

Svetlanka [38]

Its an area equation. Area is length times width.

So to start, he needs 50x80 square feet in his front yard, BUT THAT IS ONLY HALF OF THE PROBLEM. For the front yard he needs 4000 sq. feet. For the back, it is different. He needs 10x40÷2. To first simplify, we do the multiplication. This comes to 400÷2. then it is simply 200.

Now for the easy part. Take the 4000 and add 200. Answer? 4,200.

7 0

3 years ago

Janaina is trying to solve the following equation by completing the square: x^2+18x-9 = 0.She successfully rewrites the above eq

valentinak56 [21]

The Answer Is :
c = x^2 + 2bx + b^2

3 0

4 years ago