Average systolic blood pressure = x = 130 Standard deviation = s = 6
We are to find interval that represents the systolic blood pressure of middle 99.7% of the males.
According to the empirical rule: a) 68% values lie within 1 standard deviation of the mean b) 95% values lie within 2 standard deviation of the mean c) 99.7% values lie within 3 standard deviation of the mean
So, 99.7% value will lie within 3 standard deviations from the mean.
We can express this range as: ( x - 3s, x + 3s) = (130 - 3(6), 130 +3(6)) = ( 130 - 18, 130 + 18) = ( 112, 148 )
Thus the interval from 112 to 148 contains the systolic blood pressure of middle 99.7% of the males in the certain town
Let P = Pressure, V = Volume and be K = constant, by definition of Boyle's Law in which says that the volume of a gas varies inversely with the pressure, we have: P = K / V 586 = K / 5 K = 2930. Then, the pressure when the volume is 2L will be: P = 2930/2 = 1465Kpa
