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krek1111 [17]
3 years ago
11

CarMax has guaranteed to pay $500 for ANY used car - no matter how old or in what condition. You want to wait as long as possibl

e to sell and get the most bang for your luck! How long will you have to wait until your car is worth less then $500 so you can rip off CarMax? Either show your OR write an explanation of how you solved the problem. ( This is NOT a true deal from CarMax - they offered me $ 300 for my 2002 Toyota Corolla in March.
Mathematics
1 answer:
Volgvan3 years ago
8 0
After I looked up some quick information, your car loses 15-25% each year. After 5 years, it goes to only 37%. So, a car that would cost 20000 would be valued at around 7k after 5 years. So, in the first 5 years, it lost 14k. Also, a 1999 Corolla goes for 2.5k, and that's nearly 20 years. So, I'm just going to go with, based off these numbers, probably 25-30 years...if it still works by then.
Also, if you get in a heavy accident the next day, making the car unusable, you rip off your friend. The first scenario only applies if the engine works well and no accidents were on the vehicle either.
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Solve the system of equations using substitution.
faltersainse [42]

Answer:

( \frac{1}{3}, 3 )

Step-by-step explanation:

Given the 2 equations

y = 9x → (1)

6x - y = - 1 → (2)

Substitute y = 9x into (2)

6x - 9x = - 1, that is

- 3x = - 1 ( divide both sides by - 3 )

x = \frac{1}{3}

Substitute x = \frac{1}{3} into (1) for corresponding value of y

y = 9 × \frac{1}{3} = 3

Solution is ( \frac{1}{3}, 3 )

6 0
3 years ago
What is the median of 82, 4, 94, 4, 60, 91<br> And what is the mode and range
Dimas [21]

Answer:

The median is 55.833

The range is 90

The mode is 4

Step-by-step explanation:

To find median you

1. Arrange your numbers in numerical order.

2. Count how many numbers you have.

3. If you have an odd number, divide by 2 and round up to get the position of the median number.

4.If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

To find mode you put the numbers in order from least to greatest and count how many times each number occurs. The number that occurs the most is the mode.  To find range you first put all the numbers in order. Then subtract (take away) the lowest number from the highest. The answer gives you the range of the list.

4 0
3 years ago
what is the mistake in this problem and why is it wrong? 15+(√9•7)÷13 = 15+(3•7)÷3 = 15+(21)÷3 = 36+3 =12
Serggg [28]

[Edit:}

Okay! So after you have 15+(21)÷3, you have to remember PEMDAS.

PEMDAS is the order in which you solve equations.

1. Parentheses: you solve everything in the parentheses first, all while following the rules of PEMDAS

2. Exponents: after you solve the things in the parentheses, you do the exponents.

3. Then you do Multiplication or Division, solving in the order from left to right.

4. After, you do Addition or Subtraction, solving in the order from left to right.

So using PEMDAS, we'll solve 15+(21)÷3.

We do division before addition, so 21/3 is 7.

Then you add 15 to 7 and get 22 as your final answer.

Hope this helps!

7 0
3 years ago
a rectangular corn hole area at the recreation center has a width of 5 feet and a length of 10 feet. if a uniform amount is adde
harkovskaia [24]
Let
x-------------> amount added <span>to each side
</span>A-------------> area increased----------> 84 ft²

we know that
A=(10+x)*(5+x)=84-----------> 10*5+10*x+5*x+x²
50+15x+x²=84----------> x²+15x-34=0
<span>solving the second order equation
</span>x1=-17
x2=2

 the answer is x=2 ft
3 0
3 years ago
Read 2 more answers
Graph the solutions of the inequality
Fiesta28 [93]

Answer:

The graph in the attached figure

Step-by-step explanation:

Graph the solution of the inequality

t\leq -4

we know that

The solution is the interval ---> (-∞,-4]

All real numbers less than or equal to -4

In a number line the solution is the shaded area at left of t=-4 (closed circle, because the number -4 is included in the solution))

using a graphing tool

The graph in the attached figure

6 0
3 years ago
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