What is the value of x in the following equation? 5x + 12 = 6(x + 1) A. 6 B. 5 C. 24 D. 7
1 answer:
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Answer:
equation;
Center (-4,2)
Radius is
Step-by-step explanation:
Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of
Where (h,k) is center
r is the radius
So first we group like Terms together
Add 7 to both sides
Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem
and
so we have
To find our center, h is -4 and k is 2
so the center is (-4,2)
The radius is
So the radius is 3 times sqr root of 3.
Ok so we'll go ahead and solve for y first - we just need to get it alone on one side of the equal sign
Step 1: subtract 2x from each side
2x - 7y - 2x = 19 - 2x
This cancels out the 2x on the left, giving us
-7y = 19 - 2x
Step 2: divide both sides by -7
=
+
This gives us
y = -19/7 + 2x/7
That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.
When x = -3
y = -19/7 + 2x/7
y = -19/7 + 2(-3)/7
y = -19/7 - 6/7
y = -25/7
When x = 0
y = -19/7 + 2x/7
y = -19/7 + 2(0)/7
y = -19/7
When x = 3
y = -19/7 + 2x/7
y = -19/7 + 2(3)/7
y = -19/7 + 6/7
y = -13/7
Hope that helps! Feel free to ask if I can help with anything else :)