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denis23 [38]
4 years ago
14

I'm not sure how to do this....

Mathematics
2 answers:
ahrayia [7]4 years ago
6 0

Answer:

you chose the correct answer

Step-by-step explanation:

barxatty [35]4 years ago
3 0

Answer:Its not 1 or 2 i think its 12h if im wrong sorry.

Step-by-step explanation:

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How to solve 6x+25=10x-47
Irina-Kira [14]

Answer:

Step-by-step explanation:

6x+25=10x-47

16x -22

(6x + 10x) + (-47 +25)

8 0
3 years ago
Read 2 more answers
Mr. Greene is trying to decide which charter bus
Nesterboy [21]

Answer: 100 miles

Step-by-step explanation:

300+3x=500+1x

subtract 1 from both sides

300+2x=500

subtract 300 from both sides

2x=200

divide 2

x=100

6 0
3 years ago
A = ???? 4 −2
irinina [24]

Answer:

1. The matrix A isn't the inverse of matrix B.

2. |B|=12, |A|=12

Step-by-step explanation:

1. We want to know if matrix A is the inverse of matrix B, this means that if you do the product between B and A you have to obtain the identity matrix.

We have:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

and

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

A and B are 2×2 matrices (2 rows and 2 columns), if you multiply them you have to obtain a 2×2 matrix.

Then if A is the inverse of B:

B.A=I

Where,

I=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

Observation:

If you have two matrices:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A.B=\left[\begin{array}{cc}(a.e+b.g)&(a.f+b.h)\\(c.e+d.g)&(c.f+d.h)\end{array}\right]

Now:

B.A=\left[\begin{array}{cc}3&2\\1&4\end{array}\right].\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}4.3+(-2).1&4.2+(-2).4\\(-1).3+3.1&(-1).2+3.4\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}12-2&8-8\\-3+3&-2+12\end{array}\right]\\\\\\B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]

B.A=\left[\begin{array}{cc}10&0\\0&10\end{array}\right]\neq \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=I\\\\\\B.A\neq I

Then, the matrix A isn't the inverse of matrix B.

2. If you have a matrix A:

A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

The determinant of the matrix is:

|A|=ad-bc

Then the determinant of B is:

B=\left[\begin{array}{cc}3&2\\1&4\end{array}\right]

a=3, b=2, c=1, d=4

|B|=3.4-2.1\\|B|=12-2=10

The determinant of A is:

A=\left[\begin{array}{cc}4&-2\\-1&3\end{array}\right]

a=4, b=-2, c=-1, d=3

|A|=4.3-(-2).(-1)\\|B|=12-2=10

6 0
4 years ago
Find the area of the kite p=17 q =15.3
Semenov [28]

Answer:

\large\boxed{A=130.05}

Step-by-step explanation:

The formula of an area of a kite:

A=\dfrac{pq}{2}

p, q - diagonals

We have p = 17 and q = 15.3. Substitute:

A=\dfrac{(17)(15.3)}{2}=\dfrac{260.1}{2}=130.05

3 0
3 years ago
0.006 0.06 0.6 6 what's next
PIT_PIT [208]
6.0 goes next :) hope this helped
3 0
3 years ago
Read 2 more answers
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