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3 years ago

Six more than three times a number w. An expression for this phase is..? (Please help)

Mathematics

2 answers:

satela [25.4K]3 years ago

8 0

Answer:6+3w

Step-by-step explanation:

So, our number is "W"

SO, 6 more than three times w is

6+3w

Three times w=3w

Then, it says 6 more, so we add 6

sasho [114]3 years ago

8 0

Answer:

What! :) - (-() (--(

Step-by-step explanation:

MI no sabo perdon my amigo

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Todd is 81 years younger than Rosa. 3 years ago, Rosa’s age was 4 times Todd’s age. How old is Todd now?

Delvig [45]

Let t represent Todd's age now.
.. 4(t -3) -(t -3) = 81 . . . . . . 3 years ago, their differnce in ages was 81.
.. 3t -9 = 81
.. t = (81 +9)/3 = 30

Todd is 30 now.

_____
You can also work this by considering "ratio units." 3 years ago, the ratio of their ages was 4:1, a difference of 3. That difference corresponds to 81 years, so each "ratio unit" represents 81/3 = 27 years. Todd's age then was 1 ratio unit, 27 years. Now, Todd's age is 30.

8 0

3 years ago

How to expand and evaluate

Nana76 [90]

(-1.1)*(-1.1)*(-1.1)=-1.331

8 0

3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

Toby buys packs of 12 racing cars for R49,99 and sells each racing car for R10 at school

Ratling [72]

Answer:

1.1 R5.83

1.2 R70.01

1.3 58.34%

Step-by-step explanation:

Given that he buys a pack of 12 racing cars for R49,99 then the unit cost for a car which is the total cost divided by the number of cars in a pack

= R49,99/12

= R4.17

If each car is sold for R10 then the profit made on each car which is the difference between the cost and the selling price

= R10 - R4.17

= R5.83

The profit margin on one pack of 12 racing cars

Profit margin is the ratio of the profit to the total selling price

The total profit (profit on one pack of 12 racing cars)

= R5.83 * 12

=R70.01

Total selling price = R10 * 12

=R120

Margin = R70.01 / R120

= 58.34%

4 0

3 years ago

116,02 LC)

nadezda [96]

B. Triangle B and Triangle D
Triangle A has all equal sides and Triangle C is a right triangle.

5 0

3 years ago