Answer:
3t-2
Step-by-step explanation:
if anthony has t tickets multiply that by 3 with 3t and subtract 2
Assuming that this particular type of question is a system of equations one. More specifically linear equations, you would simply substitute one of the equations into the other one. Then upon doing so, plug in the x and y coordinates for the point into the x and y variables of the equation and then see if it is a solution, by checking if the left hand side of the equation equals that of the right hand side of the equation.
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
- Terms/Coefficients
- Factoring
<u>Algebra II</u>
- Exponential Rule [Powering]:

- Solving exponential equations
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Solve for </u><em><u>x</u></em>
- Rewrite:

- Set:

- Factor:

- [Division Property of Equality] Divide 3 on both sides:

- [Subtraction Property of Equality] Subtract 3x on both sides:

- [Subtraction Property of Equality] Subtract 6 on both sides:

- [Division Property of Equality] Divide -1 on both sides:

Answer:
As
so option D is correct.
Step-by-step explanation:
Given the expression
![\sqrt[3]{\left(-0.05\right)^{24}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cleft%28-0.05%5Cright%29%5E%7B24%7D%7D)
![\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
![\sqrt[3]{\left(-0.05\right)^{24}}=\left(\left(-0.05\right)^{24}\right)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cleft%28-0.05%5Cright%29%5E%7B24%7D%7D%3D%5Cleft%28%5Cleft%28-0.05%5Cright%29%5E%7B24%7D%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)




Hence, the simplification will be:
![\sqrt[3]{\left(-0.05\right)^{24}}=0.05^8](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cleft%28-0.05%5Cright%29%5E%7B24%7D%7D%3D0.05%5E8)
Therefore, option D is correct.