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Irina18 [472]
3 years ago
6

All real cube roots of 100/27

Mathematics
1 answer:
Nadya [2.5K]3 years ago
5 0

4.64158883

−2.32079442+4.01973384i

−2.32079442−4.01973384i

100 is not a perfect cube so it will never have a whole root

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I think the answer is b
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Anthony has t tickets. Charlie has 2 less than triple the number of tickets that Anthony has. In terms of t, how many tickets do
swat32

Answer:

3t-2

Step-by-step explanation:

if anthony has t tickets multiply that by 3 with 3t and subtract 2

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How to display the work for this problem. <br> -2x-3=8<br> -2x+4y=22<br> Answer (-7,2)
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7 0
4 years ago
Solve the inequality for x<br> 3^(6x+18)&lt;27^(3x)
Lera25 [3.4K]

Answer:

\displaystyle x > 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

<u>Algebra II</u>

  • Exponential Rule [Powering]: \displaystyle (b^m)^n = b^{m \cdot n}
  • Solving exponential equations

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle 3^{6x + 18} < 27^{3x}<em />

<em />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Rewrite:                                                                                                             \displaystyle 3^{6x + 18} < 3^{3(3x)}
  2. Set:                                                                                                                     \displaystyle 6x + 18 < 3(3x)
  3. Factor:                                                                                                               \displaystyle 3(2x + 6) < 3(3x)
  4. [Division Property of Equality] Divide 3 on both sides:                                  \displaystyle 2x + 6 < 3x
  5. [Subtraction Property of Equality] Subtract 3x on both sides:                       \displaystyle -x + 6 < 0
  6. [Subtraction Property of Equality] Subtract 6 on both sides:                        \displaystyle -x < -6
  7. [Division Property of Equality] Divide -1 on both sides:                                 \displaystyle x > 6
8 0
3 years ago
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Simplify ^3 sq try (-0.05)^24
Bogdan [553]

Answer:

As

  • \sqrt[3]{\left(-0.05\right)^{24}}=0.05^8

so option D is correct.                    

Step-by-step explanation:

Given the expression

\sqrt[3]{\left(-0.05\right)^{24}}

\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}

\sqrt[3]{\left(-0.05\right)^{24}}=\left(\left(-0.05\right)^{24}\right)^{\frac{1}{3}}

\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}

                  =\left(-0.05\right)^{24\cdot \frac{1}{3}}

                  =\left(-0.05\right)^8  

\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}

                  =0.05^8

Hence, the simplification will be:

\sqrt[3]{\left(-0.05\right)^{24}}=0.05^8

Therefore, option D is correct.                                            

7 0
3 years ago
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