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3 years ago

Subtract 2 16/21 - (-8 5/21). reduce if possible

Mathematics

1 answer:

amid [387]3 years ago

3 0

Answer= 11. Two negatives equals a positive so you add them together.

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Pls solve for # 5-8 <br> Thanks

MatroZZZ [7]

2x - 3 = y
-3x + 5 = y
-4/5x -2 =y
1/2x + 9 = y

7 0

3 years ago

Identify the vertex of y = x2 + 4x + 5.

Xelga [282]

ANSWER

The vertex is (-2,1)

EXPLANATION

We want to find the vertex of

$y = {x}^{2} + 4x + 5$

We complete the square to obtain,

$y = {x}^{2} + 4x + {(2})^{2} - {(2})^{2} + 5$

The first three terms forms a perfect square trinomial.

$y = {(x + 2})^{2} - 4 + 5$

The vertex form is

$y = {(x + 2})^{2} + 1$

This equation is in the form;

$y = a{(x -h})^{2} + k$

where (h,k)=(-2,1) is the vertex.

4 0

2 years ago

Read 2 more answers

The perimeter of a square is proportional to the length of its sides. This relationship can be expressed by the equation p=4s. W

stealth61 [152]

Constant of proportionality is the constant value of the two proportional quantities, in this problem p and s, where 4 is the factor of proportionality because it is constant or k.

In simple terms, p is in direct proportion to s wherein the increase or decrease in value of s results to the increase or decrease in value of p with 4 the only factor remaining unchanged.

In the above problem, the number 4 is derived from the word square. We all know that a square has 4 sides of equal lengths, therefore, the perimeter is equivalent to the product of 4 and its lenght.

3 0

2 years ago

The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative

sertanlavr [38]

The true statement about the function f(x) = -x² - 4x + 5 is that:

The range of the function is all real numbers less than or equal to 9.

<h3 /><h3>What is the domain and range for the function of y = f(x)?</h3>

The domain of a function is the set of given values of input for which the function is valid and true.

The range is the dependent variable of a given set of values for which the function is defined.

The domain of the function: f(x) = -x² - 4x + 5 are all real number from -∞ to +∞

For a parabola ax² + bx + c with the vertex $\mathbf{(x_v,y_v)}$

If a < 0, then the range is f(x) ≤ $\mathbf{y_v}$

If a > 0, then the range f(x) ≥ $\mathbf{y_v}$

Here; a = -1,

The vertex for an up-down facing parabola for a function y = ax² + bx + c is:

$\mathbf{x_v = -\dfrac{b}{2a}}$

Thus,

vertex $\mathbf{(x_v,y_v)}$ = (-2, 9)

Range: f(x) ≤ 9

Therefore, we can conclude that the range of the function is all real numbers less than or equal to 9.

Learn more about the domain and range of a function here:

brainly.com/question/26098895

#SPJ1

5 0

2 years ago

Solve the quadratic equation 3x²-3x-1=0?<br>(by using the square method)

ohaa [14]

Answer:

x=1 and x=-1/3

Step-by-step explanation:

$3x^2-2x-1=0\\\\3(x^2-\frac{2}{3}x-\frac{1}{3})=0\\ \\3(x^2-\frac{2}{3}x-\frac{1}{3}+\frac{4}{9})=3(\frac{4}{9})\\ \\ 3(x^2-\frac{2}{3}x+\frac{1}{9})=\frac{4}{3}\\ \\ 3(x-\frac{1}{3})^2=\frac{4}{3}\\ \\(x-\frac{1}{3})^2=\frac{4}{9}\\ \\x-\frac{1}{3}=\pm\frac{2}{3}$

$x-\frac{1}{3}=\frac{2}{3}\\ \\x=\frac{3}{3}\\ \\x=1$

$x-\frac{1}{3}=-\frac{2}{3}\\ \\x=-\frac{1}{3}$

Therefore, x=1 and x=-1/3

8 0

2 years ago

Subtract 2 16/21 - (-8 5/21). reduce if possible​

Subtract 2 16/21 - (-8 5/21). reduce if possible