Line d and c are bother parallel but the three options would be them
Answer:

We can divide both sides by 20 and we got:

Now we can appply natural log on both sides and we got:

Now we can divide both sides of the equation by 10 and we got:

So then the aproximate value of k is 0.30986 and rounded would be 0.31
Step-by-step explanation:
We have the following two expression:


We know that the two populations were equal 10 years after the start of the study, so then we can create the following equation:

We can divide both sides by 20 and we got:

Now we can appply natural log on both sides and we got:

Now we can divide both sides of the equation by 10 and we got:

So then the aproximate value of k is 0.30986 and rounded would be 0.31
The answer to this problem is the letter "A" which is "Multiply by 3, then add 2"
and can be written a N = 3n + 2
At first, we have initial value such n = 1
Then the second value is:
N = 3*1 + 2
N = 5
The third value is:
N = 3*5 + 2
N=17
The next values are:
N = 3*17 + 2
N= 53
The letter "A" is the inductive reasoning to the given sequence.
Answer
Find out the conversion factor for seconds to minutes and convert 135 seconds to minutes.
To prove
1 minute = 60 second
for seconds to minutes.

Therefore the conversion factor for seconds to minutes be

Now convert 135 seconds to minutes.

= 2.25 minutes
Hence proved
The first question is c i believe, I dont have time to answer the others