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Sav [38]
3 years ago
7

which of the following sets is closed under multiplication A. {0, 1, 2, 4} B. {0, 1} C. {1, 2} D. none of the sets are closed un

der multiplication
Mathematics
2 answers:
sergejj [24]3 years ago
8 0

the correct answer would be

B. {0, 1}

please mark as brainliest :)

hope i helped


Zielflug [23.3K]3 years ago
3 0

A set is closed under an operation if performing that operation on the elements of the sets results in another element of the set.

In other words, you can "combine" the elements of the set, and the result is also belonging to the set.

So:

  • Set A is not closed under multiplication: you can choose to perform 2\cdot 4 = 8, and 8 is not in the set.
  • Set B is closed under multiplication: the only multiplications you can perform are 0\cdot 0 = 0,\ 0\cdot 1 = 0,\ 1 \cdot 0 = 0,\ 1 \cdot 1 = 1. So, every possible multiplication gives 0 or 1 as result, and they both belong to the set.
  • Set C is not closed under multiplication: the multiplications you can perform are 1\cdot 1 = 1,\ 1\cdot 2 = 2,\ 2 \cdot 1 = 2,\ 2 \cdot 2 = 4. So, the possible results are 1, 2 and 4, but 4 does not belong to the set.
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June has $1.95 in dimes and nickels. She has a total of 28 coins. How many of each type of coin does she have.
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A dime = 0.10

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0.10D + 0.05N = 1.95

Replace N withe the rewritten equation above:

0.10D + 0.05(28-D) = 1.95

Use the Distributive Property:

0.10D + 1.4 - 0.05D = 1.94

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Subtract 1.4 from both sides:

0.05D = 0.55

Divide both sides by 0.05

D = 0.55 / 0.05

D = 11

Nickels = 28 - 11 = 17


There are 11 dimes and 17 nickels.


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