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Alik [6]
3 years ago
9

Aubrey and Charlie are driving to a city that is 120 mi from their house. They have already traveled 20 mi, and they are driving

at a constant rate of 50 mi/h. Complete the function that models the distance they drive as a function of time. Then complete a reasonable domain for this situation.
function notation in slope-intercept form: f(x) = ________
reasonable domain: ≤ x ≤
Mathematics
1 answer:
Zarrin [17]3 years ago
7 0

Answer:  The function that models the distance they drive is

f(x) = 50x + 20 where x is the time in hours

reasonable domain:  0 ≤ x ≤ 3

Step-by-step explanation:

examples:

95 = 50(1.5) + 20 After driving another hour and a half, they will have driven a total of 95 miles.

120 = 50(2) + 20  This means that after 2 more hours they will reach their destination.

There is a little ambiguity in the question. The function could be written as if they are starting out.  f(x) = 50t  

20 = 50(.4)  At 50 mph it took .4 hours to go 20 miles.

120 = 5(2.4)  The whole trip took 2.4 hours.

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zavuch27 [327]

Answer:

<h2>( 6 , 7 )</h2>

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )\\

From the question we have

m = ( \frac{2 + 10}{2} \:  , \:  \frac{6 + 8}{2} ) \\  =  (\frac{12}{2}  \: , \:  \frac{14}{2} ) \:  \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>( 6 , 7 )</h3>

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3 0
3 years ago
Define the value of the expression 3^2 x 3^{-5}
Tanya [424]

Answer:

Between 0 and 1

Step-by-step explanation:

The given expresion is

{3}^{2} \times  {3}^{ - 5}

Recall that:

{a}^{m}  \times  {a}^{n}  =  {a}^{m + n}

We apply this property of exponents to get;

{3}^{2}  \times  {3}^{ - 5}  =  {3}^{2 +  - 5}  =  {3}^{ - 3}

We rewrite to obtain a positive index as:

{3}^{2}  \times  {3}^{ - 5}  =  \frac{1}{ {3}^{3} }  =  \frac{1}{27}

Therefore the value of the expression is between 0 and 1.

8 0
3 years ago
1. 48 c = __qt
Scorpion4ik [409]
Number 1:
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Number 1 is D
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 Hope this really helped!
5 0
3 years ago
Read 2 more answers
If Mike can tune 4 cars in 3 hours. How many cars can Mike tune in 8 hours?
motikmotik

Answer:

10 2/3 cars

Step-by-step explanation:

We can use a ratio

4 cars            x cars

------------- = -----------

3 hours          8 hours

Using cross products

4 *8 = 3 *x

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Divide each side by 3

32/3 = 3x/3

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2 years ago
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