the diameter of a cylindrical construction pipe is 4 ft. if the pipe is 19 ft long, what s it’s volume?

Mathematics

1 answer:

choli [55]3 years ago

3 0

Answer:

76 $\pi$ or 238.76 $units^{3}$

Step-by-step explanation:

The volume of a cylinder is V = $\pi r^{2} h$

Here the radius is r = $\frac{1}{2} d$ = $\frac{1}{2}(4)=2$

The height is given as 19 ft

Then plug in all the numbers into the equation

V = $\pi (2^{2})(19) = 76\pi = 238.76 units^{3}$

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Answer asap

Lana71 [14]

Two figure in front

h=16+17 = 33 m
l=18 m
width = 13 m
Volume = lwh = 18*13*33 =7722 m^2

Two figures at the back

h=16 m
l=18+18 =36 m
width = 15 m

Volume = lwh =36*15*16 =8640 m^2

Total volume = 7722+8640 = 16362 m^2

5 0

3 years ago

Can someone please help me on this one question?

Katyanochek1 [597]

A+30 = 60
a = 30

a + 2b = 60
30+2b = 60
2b = 30
b = 15

5b - 5c = 60
5(15) - 5c = 60
5c = 15
c = 3

10c + d = 60
10(3) + d = 60
30 + d = 60
d = 30

2d + 6e = 180 - 60
2(30) + 6e = 120
6e = 60
e = 10

4f + 4e = 120
4f + 4(10) = 120
4f = 80
f = 20

5 0

3 years ago

To estimate the length of the lake, caleb starts at one end of the lake and walk 95m. He then turns a 60° angle and walks on a n

aivan3 [116]

Answer:

Length of the lake is 97.30 m

Step-by-step explanation:

We have given Caleb starts at one end of the lake and walk 95 m

So $d_1=95m$