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storchak [24]
3 years ago
11

the diameter of a cylindrical construction pipe is 4 ft. if the pipe is 19 ft long, what s it’s volume?

Mathematics
1 answer:
choli [55]3 years ago
3 0

Answer:

76\pi or 238.76 units^{3}

Step-by-step explanation:

The volume of a cylinder is V = \pi r^{2} h

Here the radius is  r = \frac{1}{2} d = \frac{1}{2}(4)=2

The height is given as 19 ft

Then plug in all the numbers into the equation

V = \pi (2^{2})(19) = 76\pi = 238.76 units^{3}

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A piece of fabric is 1/3 yard by 3 5/8 yards.
tankabanditka [31]

Answer:

sorry if this is wrong

Step-by-step explanation:

a. 3

b.15

c.8

3 0
2 years ago
If s is an increasing function, and t is a decreasing function, find Cs(X),t(Y ) in terms of CX,Y .
Sedbober [7]

Answer:

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

Step-by-step explanation:

Let's introduce the cumulative distribution of (X,Y), X and Y :

F(X,Y)(x,y)=P(X≤x,Y≤y)

  • FX(x)=P(X≤x)
  • FY(y)=P(Y≤y).

Likewise for (s(X),t(Y)), s(X) and t(Y) :

F(s(X),t(Y))(u,v)=P(s(X)≤u

  • t(Y)≤v)
  • Fs(X)(u)=P(s(X)≤u)
  • Ft(Y)(v)=P(t(Y)≤v).

Now, First establish the relationship between F(X,Y) and F(s(X),t(Y)) :

F(X,Y)(x,y)=P(X≤x,Y≤y)=P(s(X)≤s(x),t(Y)≥t(y))

The last step is obtained by applying the functions s and t since s preserves order and t reverses it.

This can be further transformed into

F(X,Y)(x,y)=1−P(s(X)≤s(x),t(Y)≤t(y))=1−F(s(X),t(Y))(s(x),t(y))

Since our random variables are continuous, we assume that the difference between t(Y)≤t(y) and t(Y)<t(y)) is just a set of zero measure.

Now, to transform this into a statement about copulas, note that

C(X,Y)(a,b)=F(X,Y)(F−1X(a), F−1Y(b))

Thus, plugging x=F−1X(a) and y=F−1Y(b) into our previous formula,

we get

F(X,Y)(F−1X(a),F−1Y(b))=1−F(s(X),t(Y))(s(F−1X(a)),t(F−1Y(b)))

The left hand side is the copula C(X,Y), the right hand side still needs some work.

Note that

Fs(X)(s(F−1X(a)))=P(s(X)≤s(F−1X(a)))=P(X≤F−1X(a))=FX(F−1X(a))=a

and likewise

Ft(Y)(s(F−1Y(b)))=P(t(Y)≤t(F−1Y(b)))=P(Y≥F−1Y(b))=1−FY(F−1Y(b))=1−b

Combining all results we obtain for the relationship between the copulas

C(X,Y)(a,b)=1−C(s(X),t(Y))(a,1−b).

7 0
3 years ago
Which equation represents a line which is perpendicular to the y-axis?
erma4kov [3.2K]

Answer:

y = 5

Step-by-step explanation:

The y-axis and any lines that are parallel to it are vertical. Therefore, a line that would be perpendicular to the y-axis would need to be horizontal. All horizontal lines have a slope equal to 0 and are represented by the equation y = a constant, or a single number with no variables.  

The only option that follows that format is y = 5, thus that is the answer.  

6 0
2 years ago
The mass of a ball is 128 g. It has a density of 0.5 g/cm³.
liraira [26]

Answer:

The volume of the ball is 256 cm³

Step-by-step explanation:

we know that

The density is equal to the ratio of the mass by the volume

D=m/V

Solve for V

The volume is equal to the ratio of the mass by the density

V=m/D

In this problem we have

m=128 g

D=0.5 g/cm³

substitute

V=128/0.5=256 cm³

7 0
3 years ago
Rewrite using a negative exponent.<br> 1/a ^4
vesna_86 [32]

Answer: a^-4

Step-by-step explanation:

  \frac{1-4}{a^4-4}  = a^-4

8 0
2 years ago
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