the marked angles are complementary → B
All 3 triangles are right with one angle = 90°
the sum of the angles in a triangle = 180°
thus the remaining 2 marked angles sum to 90°, thus are complementary
(x - 2)^2 will always be positive and will have a minimum value of 0
so f(x) will have minimum of 2
Range is [2,∞)
First, you must change all of this into improper fractions, like shown below.

Now you must change the sign.

Then we must reciprocalize 2/3.

Now we multiply, to get 2 4/10.
I believe C. Measuring the length from one end of the field tot he other would be the most reasonable answer, because Area = Length x Width