Question

The alphabet game costs $.25 to play. Before the game, 26 slips of paper with a different letter of the alphabet on it are put into a bag. A player draws one slip from the bag. If the player draws a vowel (A, E, I, O, or U), he or she wins $1. If a player plays the alphabet game 2 times in a row, replacing the slip of paper after each turn, what is the probability that they win twice? Write as a fraction.

Answer 1

Answer: 25/676

Step-by-step explanation:

Number of possible outcomes = 26

In other to win, one must draw must be either (A, E, I, O or U)

Therefore required drws to win = 5

First draw:

P(win) = Total required outcome / Total possible outcome

P(win) = 5/26

Second draw:

P(win) = Total required outcome / Total possible outcome

P(win) = 5/26

Therefore,

P(winning twice) = (5/26) × (5/26) = 25/676