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Juli2301 [7.4K]
3 years ago
13

The alphabet game costs $.25 to play. Before the game, 26 slips of paper with a different letter of the alphabet on it are put i

nto a bag. A player draws one slip from the bag. If the player draws a vowel (A, E, I, O, or U), he or she wins $1. If a player plays the alphabet game 2 times in a row, replacing the slip of paper after each turn, what is the probability that they win twice? Write as a fraction.
Mathematics
1 answer:
julsineya [31]3 years ago
8 0

Answer: 25/676

Step-by-step explanation:

Number of possible outcomes = 26

In other to win, one must draw must be either (A, E, I, O or U)

Therefore required drws to win = 5

First draw:

P(win) = Total required outcome / Total possible outcome

P(win) = 5/26

Second draw:

P(win) = Total required outcome / Total possible outcome

P(win) = 5/26

Therefore,

P(winning twice) = (5/26) × (5/26) = 25/676

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The equation represents the total liters of acid that are needed is,

0.5x+0.9y=6

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<h3>What is allegation?</h3>

Allegation is a method to find the ratio in which two or more indignant are mixed to produce a mixture or solution.

Given information-

A scientist needs 10 L of a solution that is 60% acid.

The percentage of two acid solution are 50% and 90%.

Variable<em> x</em><em> </em>represent the number of liters of the 50% solution.

Variable<em> y </em>represent the number of liters of the 90% solution.

Quantity of acid from 50% solution is 0.5x liters, and quantity of acid from 90% solution is 0.9x liters.

As the scientist needs 10 L of a solution that is 60% acid. Therefore the quantity of acid in 60 percent acid solution is,

a=10\times\dfrac{60}{100} \\a=6

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0.5x+0.9y=6

This is the required equation.

Hence the equation represents the total liters of acid that are needed is,

0.5x+0.9y=6

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