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3 years ago

A regulation soccer field has an area of 59,400 square feet. If the length is 330 feet, what is the width in feet

Mathematics

1 answer:

Juli2301 [7.4K]3 years ago

4 0

Answer:

The answer is 180 feet.

Step-by-step explanation:

Here's your equation. (330 x W = 59,400). If you want to find the width then divide 59,400 by 330 and you get 180 feet.

You can check by multiplying 330 and 180 which will result in 59,000.

So the correct answer is 180 feet.

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ANSWER

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${h}^{2} = {y}^{2} + {4}^{2}$
This implies that,

${h}^{2} = {y}^{2} + 16...eqn1$

Also,

${h}^{2} + {x}^{2} = {16}^{2} ...eqn2$

And

${y}^{2} + {12}^{2} = {x}^{2}$

${y}^{2}={x}^{2} - 144 ...eqn3$

Put equation 1 into equation 2.

This will give us,

${y}^{2} + 16 + {x}^{2} = {16}^{2}$

${y}^{2} +{x}^{2} = {16}^{2} - 16$

${y}^{2} +{x}^{2} =16 ( 16 - 1)$

${y}^{2} +{x}^{2} =240...eqn4$

We put equation 3 into equation 4,

${x}^{2} - 144+{x}^{2} =240$

We simplify to get,

$2 {x}^{2} = 384$

${x}^{2} = 192$

$x = \sqrt{192}$

$x = 8 \sqrt{3}$

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