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3 years ago

Find the slope of the line that passes through the pair of points (3,-3) (3.-4)

1 answer:

7 0

ANSWER
• Undefined Slope
• The equation of the line would be x=3

EXPLANATION
1) -4-(-3)=-1

2) 3-3=0

3) Since this is an undefined slope, the equation of the line would be x=3.

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The equation of line L, is y = 5x + 1

Lynna [10]

Answer:

see explanation

Step-by-step explanation:

Parallel lines have equal slopes.

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 5x + 1 ← is in slope- intercept form

with slope m = 5

Rearrange 2y - 10x + 3 = 0 into this form

Add 10x to both sides

2y = 10x ( subtract 3 from both sides )

2y = 10x - 3 ( divide all terms by 2 )

y = 5x - $\frac{3}{2}$ ← in slope- intercept form

with slope m = 5

Since both lines have a slope of 5 then they are parallel.

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3 years ago

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

lubasha [3.4K]

Answer:

The answer is option C.

Step-by-step explanation:

The arithmetic sequence is given by

$A(n) = - 6 + (n - 1)( \frac{1}{5} )$

where n is the number of terms

For the first term

n = 1

So we have

$A(1) = - 6 + (1 - 1)( \frac{1}{5} )$

$= - 6 + (0)( \frac{1}{5} )$

$= - 6$

For the fourth term

n = 4

$A(4) = - 6 + (4 - 1)( \frac{1}{5} )$

$= - 6 + (3)( \frac{1}{5} )$

$= - 5 \frac{2}{5}$

For the tenth term

n = 10

$A(10) = - 6 + (10 - 1)( \frac{1}{5} )$

$= - 6 + (9)( \frac{1}{5} )$

$= - 4 \frac{1}{5}$

Hope this helps you

4 0

3 years ago

Find f^-1(x) for f(x) = 1/x^3

kow [346]

Answer: $f^{-1}(x) = \frac{\sqrt[3]{x^{2}}}{x}$

Step-by-step explanation:

$y = \frac{1}{x^{3}}$

Inverse is when you swap the x's and y's and then solve for "y":

$x = \frac{1}{y^{3}}$

$y^{3} = \frac{1}{x}$

$y = \frac{1}{\sqrt[3]{x}}$

$y = \frac{1}{\sqrt[3]{x}}*(\frac{\sqrt[3]{x}}{\sqrt[3]{x}})^{2}$

$y = \frac{\sqrt[3]{x^{2}}}{x}$

4 0

3 years ago

Express the product in simplest form.

Romashka [77]

$\frac{8}{2x+8} * \frac{ x^{2}-16 }{4}$

1. Cross cancel
$\frac{4}{2x+8}* \frac{ x^{2} -16}{1}$

2. Multiply numerators
4*x²-16 = 4x²-64

3. Multiply denominators
2x+8*1 = 2x+8

$\frac{4 x^{2} -64}{2x+8}$

4. Divide
$\frac{4 x^{2} -64}{2x+8} = 2x-8$

5. Simplify
2(x-4)

Answer is 2(x - 4)

4 0

3 years ago

Is 2,107,954 even or odd

RSB [31]

Answer:

Even

Step-by-step explanation:

Ends in 4

4 0

2 years ago

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