In the diagram, P1P2 and Q1Q2are the perpendicular bisectors of AB¯¯¯¯¯ and BC¯¯¯¯¯, respectively. A1A2 and B1B2 are the angle b
isectors of ∠A and ∠B, respectively. What is the center of the circumscribed circle of ΔABC?
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1 answer:
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Answer:
Step-by-step explanation:
the equation for finding the slope of a line when given two points is , aka the change in y over the change in x.
pick one of your coordinate pairs to be and
. it doesn't matter which coordinate pair you choose as long as you keep them as
and
. the remaining coordinate pair will be
and
.
for this example, i'll use (2, 10) for and
and (6, 7) for
and
.
<em>**before i begin, i just want to note that you can do these next four steps in any order that you want. i personally prefer to plug in my y-values first and then my x-values, but you can choose to instead plug in the values of each coordinate pair (like starting by plugging in the coordinate pair (2, 10) with 10 for </em> and 2 for
<em>). it's up to you. i'm going to explain the steps by plugging in my y-values first and then my x-values because that's the way i normally do it.</em>
<em />
first, start by plugging in the y-value from the coordinate pair of your choosing in for . since i chose (2, 10) for
and
, i'll plug in 10 for
.
⇒
then plug in the remaining coordinate pair's y-value in for . since the coordinate pair that's left is (6, 7), i will plug in 7 for
.
⇒
now i'm going to plug in the x-values. i chose (2, 10) to plug in for and
, so now i'll plug in 2 for
.
⇒
and all that's left to plug in is the x-value from (6, 7), so i will plug that in for .
⇒
after plugging in all the values, you have .
subtract 10 - 7 as well as 2 - 6.
⇒
cannot be simplified, therefore the slope of the line is
or
.
i hope this helps! have a lovely day <3
Use the distance formula:
<span>
<span>
Plug in the given coordinates:
</span><span>
<span>
Simplify:
</span>
You can leave it as:
or in decimal form as: 7.2
</span></span>
<span>
<span>
Plug in the given coordinates:
</span><span>
<span>
Simplify:
</span>
You can leave it as:
</span></span>