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Sav [38]
3 years ago
13

Which attribute is NOT always true for a rhombus?

Mathematics
2 answers:
yaroslaw [1]3 years ago
7 0

Answer:

the answer would be b)

Step-by-step explanation:

Reil [10]3 years ago
4 0

Answer:

B) four right angles

Step-by-step explanation:

The definition of a rhombus is that it is an equilateral quadrilateral.

This definition knocks out A.

C and D can also be knocked out because opposite angles are congruent, so they both must also be true.

Also, B is the requirement for a square, not a rhombus.

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Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
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Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

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\implies b^2=81-49

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We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1

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