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3 years ago

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What are the real or imaginary solutions of the polynomial equation?. . 27x^3 + 125 = 0

1 answer:

Natasha2012 [34]3 years ago

6 0

We are given the equation 27 x3 + 125 = 0 and is asked in the problem the value of x. In this case, the equation is expressed as 27x3 = -125; x1 = -5/3; x2 =(-15-√-675)/18=(-5-5i√ 3 )/6= -0.8333-1.4434i ; x3 =(-15+√-675)/18=(-5+5i√ 3 )/6= -0.8333+1.4434i

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Read 2 more answers

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Art [367]

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Step-by-step explanation:

Exponential distribution:

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