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nika2105 [10]
3 years ago
14

What are the real or imaginary solutions of the polynomial equation?. . 27x^3 + 125 = 0

Mathematics
1 answer:
Natasha2012 [34]3 years ago
6 0
We are given the equation 27 x3 + 125 = 0 and is asked in the problem the value of x. In this case, the equation is expressed as 27x3 = -125; x1 = -5/3;  x2 =(-15-√-675)/18=(-5-5i√ 3 )/6= -0.8333-1.4434i ;  x3 =(-15+√-675)/18=(-5+5i√ 3 )/6= -0.8333+1.4434i
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vekshin1

Answer:

for the first one- 1/8 0.25= decimal and percent=12.5%

Second 8 boxes and shade in 6    0.75=decimal     75%    

Step-by-step explanation:

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4 years ago
WILL MARK BRAINLIEST PLZ HELP
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Jet001 [13]

Answer:

\large\boxed{-10x^6+5x^5+15x^4-10x^3-6x^2}

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given that the radius of the circle is 3 units.

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Expression to find the measure of θ in radians:

The expression can be determined using the formula,

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Substituting S = π and r = 3, we get;

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Answer:

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