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Morgarella [4.7K]
3 years ago
7

I have to solve for H​

Mathematics
1 answer:
kiruha [24]3 years ago
5 0

Answer:

h = \frac{3v}{\pi r^{2} }

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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What is it counting by?
baherus [9]
It’s multiplying by 4.
1x4=4
4x4=16
16x4=64
3 0
3 years ago
Write the ratio as a fraction in simplest form. 27 to 72
Mademuasel [1]

Answer: The ration for 27:71, would be 3/8. Hope this helps!

4 0
3 years ago
Please help
stiks02 [169]

Answer:

270 cubic inches

Step-by-step explanation:

first you multiply 9 times 5 which equals 45 and then you multiply 45 by 6 to get 270. (for volume its length times width times height)

3 0
3 years ago
A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40
bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that s = 25, \sigma = 400. We want to find n, so:

s = \frac{\sigma}{\sqrt{n}}

25 = \frac{400}{\sqrt{n}}

25\sqrt{n} = 400

\sqrt{n} = \frac{400}{25}

\sqrt{n} = 16

(\sqrt{n})^2 = 16^2[tex][tex]n = 256

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

45.14% probability that the point estimate was within ±15 of the population mean

3 0
3 years ago
How many positive integers less than 250 are multiples of 5, but not multiples of 10?
SashulF [63]

Answer:

Step-by-step explanations: sometimes 5 times (number) is 250 but in this case your teacher did not tell you to multiply it by 10 but instead multiplying it by 5

8 0
3 years ago
Read 2 more answers
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