All categories

2 years ago

I have to solve for H

Mathematics

1 answer:

kiruha [24]2 years ago

5 0

Answer:

h = $\frac{3v}{\pi r^{2} }$

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

You might be interested in

Slope -3; y intercept -4

levacccp [35]

Y=-3x-4 is the equation

6 0

3 years ago

Graph the following quadratic equation<br> f (x) = x² - 4x + 3

PilotLPTM [1.2K]

Answer:

Step-by-step explanation:

5 0

2 years ago

Find the number that belongs

tangare [24]

Answer:

2.7

Step-by-step explanation:

322/7=46

46*125=2.71739

round off

2.7

4 0

3 years ago

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0

1 year ago

X+7=4 Algebraic equation

Vaselesa [24]

The answer is x=

-3

Hope I helped!

5 0

2 years ago

Read 2 more answers

I have to solve for H​

I have to solve for H