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elena55 [62]
2 years ago
7

Me ajudem com a 3º questão

Mathematics
1 answer:
Alisiya [41]2 years ago
7 0

I can't read that language but I'll guess it says write a second degree equation then solve for n when d=10.

10 = \dfrac{n(n-3)}{2}

20 = n^2 - 3n

n^2 - 3n - 20 = 0

Answer: n² - 3n - 20 = 0

That doesn't factor so there is no integer n solution.

That means there are no polygons with 10 diagonals.

n = \frac 1 2(3 \pm \sqrt{89})

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