All categories

3 years ago

How many posible solutions for x-3y=-3 and -2x+6y=12

Mathematics

1 answer:

Alexus [3.1K]3 years ago

7 0

Answer:

there are no solutions

Step-by-step explanation:

x-3y=-3

-2x+6y=12

multiply the first equation by 2

2( x-3y)=-3*2

2x-6y = -6

add the 2 equations together

2x-6y = -6

-2x+6y=12

-------------------

0 = -6

this is not true

so there are no solutions

You might be interested in

NEED ANSWER ASAP!!!!

lesya692 [45]

Answer:

1st option

Step-by-step explanation:

To find the difference of the given matrices, we just need to subtract the corresponding elements of the two matrices as shown below:

$\left[\begin{array}{cc}-4&8\\3&12\end{array}\right] -\left[\begin{array}{cc}2&1\\-14&15\end{array}\right] \\\\ \\ =\left[\begin{array}{cc}-4-2&8-1\\3-(-14)&12-15\end{array}\right]\\\\ \\ =\left[\begin{array}{cc}-6&7\\17&-3\end{array}\right]$

Thus, 1st option gives the correct answer

7 0

3 years ago

Read 2 more answers

Please help! just tell me the letter answer please :(

Sergio039 [100]

Answer: B. 5

Hope this helps! :)

7 0

3 years ago

Need help on 4-7 plz

anastassius [24]

4. 54 + 63 + 54=171
5. 3+3+75=81
6. 20+68=89
7. 120+180=300 x 1.48=$444

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%2018-%20%5Csqrt%202" id="TexFormula1" title="\sqrt 18- \sqrt 2" alt="\sqrt 18- \sqrt 2

zimovet [89]

The answer is 2√2

√18 - √2
3 √2 - √2 = 2√2

4 0

2 years ago

Read 2 more answers

Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 )left parenthesis, 0, comma

steposvetlana [31]

Answer:

$\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }$

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) $\frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }$ .

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

$\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }$

8 0

3 years ago