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natima [27]
3 years ago
13

In your computation, approximate its value as 3.14.

Mathematics
1 answer:
andrey2020 [161]3 years ago
7 0

Answer: d

Step-by-step explanation:

Find the area of the rectangle.

A=l*w\\A=(15in)(12in)\\A=180in^2

Find the area of the base of the semicircle.

A=\pi r^2

12 in would be the diameter, divide by 2 to get the radius.

\frac{12}{2}=6

Plug this into the formula.

A=(3.14)(6)^2\\A=113.04in^2

Since we do not have a full circle but a semi one instead, we must divide our result by 2.

\frac{113.04}{2}=56.52in^2

Add both areas.

180+56.52=236.52in^2

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I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct
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*If you need me to do #5, DM me!

3. 
The area of a triangle can be given by (just plug and chug as always):
A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2
A_r = bh = 12(8) = 96m^2
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So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
A_t = \frac{1}{2}bh
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2
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