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zhenek [66]
3 years ago
15

Solve 2x^2-21x-36=0

Mathematics
2 answers:
Elena-2011 [213]3 years ago
8 0
2x^2-21x-36=0 

x_{1,\:2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a} 

\mathrm{For\:}\quad a=2,\:b=-21,\:c=-36:\quad x_{1,\:2}=\frac{-\left(-21\right)\pm \sqrt{\left(-21\right)^2-4\cdot \:2\left(-36\right)}}{2\cdot \:2} 

x=\dfrac{-\left(-21\right)+\sqrt{\left(-21\right)^2-4\cdot \:2\left(-36\right)}}{2\cdot \:2}:\quad 12 

x=\dfrac{-\left(-21\right)-\sqrt{\left(-21\right)^2-4\cdot \:2\left(-36\right)}}{2\cdot \:2}:\quad -\dfrac{3}{2} 

x=12,\:x=-\dfrac{3}{2}
Alinara [238K]3 years ago
7 0
The answer is B. Hope that help.

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