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3 years ago

Complete. What is the Original Price?

Mathematics

2 answers:

FromTheMoon [43]3 years ago

7 0

The original price would be $450

Pani-rosa [81]3 years ago

3 0

90 80% disocunt so what you do is divide that then let me know what you got

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What time would it be if you rotated the hour hand 90° counterclockwise? [[ READ ATTACHMENTS ]]

kkurt [141]

Answer:

Step-by-step explanation:

4 0

3 years ago

What are the solutions to the system of equations graphed below?

PIT_PIT [208]

Answer:

(-3,-3) and at (0,6)

Step-by-step explanation:

The solution to the system of equations is where the graphs intersect

The graphs intersect at (-3,-3) and at (0,6)

3 0

3 years ago

F(x) =2x + 5 and g(x)=5, find(fg)(x)

irakobra [83]

Answer: C) 10x + 25

Step-by-step explanation:

f(x) = 2x + 5 , g(x) = 5

(fg)(x) = (2x + 5) * 5

= 10x + 25

5 0

3 years ago

WHO CAN solve it Please !

Mariulka [41]

Answer:

a) True

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

Step-by-step explanation:

Step(i):-

Given that the definite integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha$

we know that the trigonometric formula

sin²∝+cos²∝ = 1

cos²∝ = 1-sin²∝

step(ii):-

Now the integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha$

= $\int\limits^\pi _0 {cos\alpha } \, dx$

Now, Integrating

$= ( sin\alpha )_{0} ^{\pi }$

= sin π - sin 0

= 0-0

= 0

Final answer:-

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

5 0

3 years ago

Combine like terms. What is a simpler form of the expression? -3(-4y + 3) + 7y

sashaice [31]

19y-9. you distribute -3 into (-4y +3) to get 12y -9 and then you combine like terms so 12y +7y to get 19y and you still have the -9 so the simplest form would be 19y-9

4 0

3 years ago