Answer:
and 
Step-by-step explanation:
Given
Bisector: CD
of Line AB
Required
Apply Pythagoras Theorem
From the question, CD bisects AB and it bisects it at D.
The relationship between AB and CD is given by the attachment
Considering ACD
From the attachment, we have that:
By Pythagoras Theorem, we have
Considering CBD
From the attachment, we have that:
By Pythagoras Theorem, we have:
Answer:
Part 1) The value of x is 50°
Part 2) The measure of angle LOK is 114°
Option C
Step-by-step explanation:
we know that
if two angles are supplementary, then their sum is equal to 180 degrees
so
(x+64)°+66°=180°
solve for x
x+130°=180°
x=180°-130°=50°
Find the measure of angle LOK
∠LOK=(x+64)°
∠LOK=(50+64)°=114°
To find the area, move each semicircle to fill up the square, you'll see there are three squares, each with an area of 4*4=16, so the total area is 3*16=48
Now the perimeter:
the perimeter of a circle is π times the diameter.
perimeter of each semicircle: (1/2)π*4=2π
there are altogether 6 arches and two straight sides, so the total is
2π*6+4*2=12π+8
the area is 48 square units, the perimeter is 12π+8 units.
Answer:
Step-by-step explanation:
Given
The question is illustrated with the attached image
Required
Find 
To do this, we use sine formula
i.e.
So, we have:
Take arc sin
Answer:
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