Answer:
the answer is option A. Because if it is a parallelogram QR must be parallel to TS and QT must be parallel to RS
Answer:
Breyers is the correct answer
Step-by-step explanation:
$4.50/30 oz = .15
$15.36/128 oz = .12
$2.88/16 oz = .18
-4
Step-by-step explanation:
-4z² + z²
let's assume you have z² and you're owing 4z², you'll pay the z² you have and you'll still owe 4
so that is -4
Answer:
y =
+ 
Step-by-step explanation:
y''- 9 y' + 18 y = t²
solution of ordinary differential equation
using characteristics equation
m² - 9 m + 18 = 0
m² - 3 m - 6 m+ 18 = 0
(m-3)(m-6) = 0
m = 3,6
C.F. = 
now calculating P.I.


hence the complete solution
y = C.F. + P.I.
y =
+ 
Answer:
4b. −6x + y = −4
4a. 7x + 4y = −12
3b. y = ½x + 3
3a. y = −6x + 5
2b. y + 2 = −⅔(x + 3)
2a. y - 3 = ⅘(x - 5)
1b. y = -x + 5
1a. y = 5x - 3
Step-by-step explanation:
4.
Plug the coordinates into the Slope-Intercept Formula first, then convert to Standard Form [Ax + By = C]:
b.
2 = 6[1] + b
6
−4 = b
y = 6x - 4
-6x - 6x
_________
−6x + y = −4 >> Standard Equation
a.
4 = −7⁄4[-4] + b
7
−3 = b
y = −7⁄4x - 3
+7⁄4x +7⁄4x
____________
7⁄4x + y = −3 [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
4[7⁄4x + y = −3]
7x + 4y = −12 >> Standard Equation
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3.
Plug both coordinates into the Slope-Intercept Formula:
b.
5 = ½[4] + b
2
3 = b
y = ½x + 3 >> EXACT SAME EQUATION
a.
−1 = −6[1] + b
−6
5 = b
y = −6x + 5
* Parallel lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>].
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2.
b. y + 2 = −⅔(x + 3)
a. y - 3 = ⅘(x - 5)
According to the <em>Point-Slope Formula</em>, <em>y - y₁ = m(x - x₁)</em>, all the negative symbols give the OPPOSITE TERMS OF WHAT THEY REALLY ARE, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.
__________________________________________________________
1.
b. y = -x + 5
a. y = 5x - 3
Just write out the Slope-Intercept Formula as it is given to you.
I am joyous to assist you anytime.