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stepan [7]
3 years ago
9

What is the slope of the equation of a line that passes through the point

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
8 0

Answer:

y = 0.8x – 4

or

y = 4 /5x- 4

Step-by-step explanation:

the slope is 4/5 or 0.8 either one work :)

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मूल्यमान्यता काे वाक्य​
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Step-by-step explanation:

हामीले सामाजिक मूल्यमान्यतालाई महत्त्व दिनुपर्दछ।

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20 POINTS<br><br> Part E<br> How many of the 320 million Americans would you predict wear glasses?
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About 164 million U.S. adults
3 0
2 years ago
Which of these was not a factor in the build up to World War I?
sammy [17]

Answer:

A familial dispute amongst monarchs as to who inherited territory in the balkans.

Step-by-step explanation:

I learned from my mistake and it gave me that this was the answer.

Goodluck

4 0
3 years ago
Read 2 more answers
A. A researcher reads that in the population of US students, the average income of students is $1500. In a random sample of 300
MrRa [10]

Answer:

A. Value of t = -1.7974 .

B. If the t-score that was calculated was between 1.7 and 1.9, we will not be able to reject the null hypothesis.

C. No, we can't reject the null hypothesis with 99% confidence.

Step-by-step explanation:

We are given the population mean income of students, \mu = $1500.

Let,   Null Hypothesis, H_0 : \mu = $1500

Alternate Hypothesis, H_1 : \mu < $1500

A. The one-tailed t statistics used here is ;

               \frac{xbar - \mu}{\frac{s}{\sqrt{n} } } follows t_n_-_1     where, xbar = sample mean = $1445

                                                              s = sample standard deviation = $530

                                                              n = sample size = 300

Test Statistics  = \frac{1445 - 1500}{\frac{530}{\sqrt{300} } } follows t_2_9_9

         Value of t      = -1.7974

<em>Now, at 5% level of significance the t table will give a critical value of -1.9696. Since our test statistics is greater than critical value as -1.7974 > -1.9696 so we have insufficient evidence to reject null hypothesis and conclude that population mean is $1500 and sample mean is less than the population mean</em>.  

B. If the t-score that was calculated above was between 1.7 and 1.9 then also we haven't rejected the null hypothesis as then also our test statistics doesn't lie in the rejection region as 1.7 to 1.9 is greater than -1.9696. And we conclude that sample and the population mean are not same.

C. <em>99% Confidence Interval for </em>\mu = [xbar - 1.9696*\frac{s}{\sqrt{n} } , xbar + 1.9696*\frac{s}{\sqrt{n} }]

                                                     = [1445 - 1.9696*\frac{530}{\sqrt{300} } , 1445 + 1.9696*\frac{530}{\sqrt{300} }]

                                                     = [ 1384.731 , 1505.269 ]

Since, $1500 lies in this 99% confidence interval so still we can't reject null hypothesis.

         

7 0
3 years ago
How do i do this problem?
morpeh [17]
2 1/3 + 1 3/4 = 3 10/12 

5/6 = 10/12

3 10/12 + 10/12 = 3 20/12 = 4 8/12 = 4 hours 40 minutes

4 hours 5 minutes away from 10:05 would be 6 pm

subtract 35 from that and you get 5:25 pm
3 0
2 years ago
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