Question

(2x^3+6x-1)+(3x^2-7x)

Answer 1

For this case we must simplify the following expression:

$(2x ^ 3 + 6x-1) + (3x ^ 2-7x)$

We eliminate the parentheses taking into account that:

$+ * + = +\\+ * - = -$

So, we have:

$2x ^ 3 + 6x-1 + 3x ^ 2-7x =$

We add similar terms taking into account that:

Different signs are subtracted and the sign of the major is placed:

$2x ^ 3 + 3x^2-x-1$

Answer:

$2x ^ 3 + 3x^2-x-1$