Length of rectangle = 5 less than 2x width
Perimeter = 146 cm
<u>Equations we will use...</u>
w = width
(2w - 5) = length (l)
perimeter (p) = 2(l + w)
<u>Substitute equation for </u><u>length</u><u> into equation for </u><u>perimeter</u>
p = 2(l + w)
146 = 2((2w - 5) + w) [use distributive prop.]
146 = 4w - 10 + 2w [combine like terms]
146 = 6w -10 [solve for w]
156 = 6w
w = 26 cm
<u>Now substitute width back into the </u><u>equation</u><u> for length...</u>
l = 2w - 5
l = 2(26) - 5
l = 47
Double check to make sure values added up to 146 cm
w + w + l + l = 146
26 + 26 + 47 + 47 = 146
146 = 146
Therefore, the width is 26 cm and the length is 47 cm.
Answer: 2.6
Step-by-step explanation:
28-15=13
13/5=2.6
Good luck! :)
Answer:
AC congruent to EC
Step-by-step explanation:
This problem is asking specifically to prove triangles congruent using HL.
HL is a method of proving triangles congruent. HL stands for Hypotenuse-Leg. If you can show that the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg, respectively, of another triangle, then the triangles are congruent.
Looking at triangle ABC and EDC, we see that the legs AB and ED are congruent. We already have a pair of corresponding congruent legs. Now we need a pair of hypotenuses.
You need AC congruent to EC.
The length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4
A rectangle is a quadrilateral in which opposite sides are equal and parallel to each other. The area of a rectangle is:
Area = length * width
From the image:
Length of AB = x + 4
Length of BC = x + 6
The area of rectangle ABCD = Length of AB * Length of BC
28 = (x + 4)(x + 6)
x² + 10x + 24 = 28
x² + 10x = 4
Comparing with x² + ax = b gives:
a = 10, b = 4
Therefore the length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4
Find out more at: brainly.com/question/15019502
