Answer:
Consider the following code.
Explanation:
save the following code in read_and_interp.m
function X = read_and_interp(s)
[m, n] = size(s);
X = zeros(m, 1);
for i = 1:m
if(str2num(s(i, 2:5)) == 9999)
% compute value based on previous and next entries in s array
% s(i, 2:5) retrieves columns 2-5 in ith row
X(i,1) = (str2num(s(i-1 ,2:5)) + str2num(s(i+1,2:5)))/2;
else
X(i,1) = str2num(s(i,2:5));
end
end
end
======================
Now you can use teh function as shown below
s = [ 'A' '0096' ; 'B' '0114' ; 'C' '9999' ; 'D' '0105' ; 'E' '0112' ];
read_and_interp(s)
output
ans =
96.000
114.000
109.500
105.000
112.000
Answer:
A. Is the page-replacement algorithm most often implemented.
Explanation:
This algorithm is used when a page that is not present in memory is called, leading to the Operating System to replace one of the existing pages with the needed one. There are different replacing algorithms in order to decide which page will be replaced.
This algorithm is implemented to reduce the number of failures and provide a better funcionality and speed the process by discarding pages that won't be used for a long period of time.
Answer:
Memory-mapped I/O and port-mapped I/O are two complementary methods of performing input/output between the central processing unit and peripheral devices in a computer. An alternative approach is using dedicated I/O processors, commonly known as channels on mainframe computers, which execute their own instructions.
Answer:
They’ll have to be 2 answers first, when 2 answers are given, you can choose which is branlyis. If there are no 2 answers, you can’t choose.
Answer:
The answer is IP-sec.
Explanation:
0.75 miles of range is a low distance for a WAN (Wide Area Network) so a point-to-point WAN tehcnology such as IP-sec or SD-WAN can be preferred. But the least expensive option would be choosing IP-sec as specified in the question.
I hope this answer helps.
