3 years ago

Is #19. For a correct and can someone explain this to me please?

1 answer:

8 0

I believe it's right, but I'm not sure if saying x^2 versus x*x makes a difference, so I personally would put x*x to be safe.

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Please can someone show me how to work this out step by step without a calculator

Artyom0805 [142]

$2\sqrt8\times8\sqrt2=(2\times8)\sqrt{8\times2}=16\sqrt{16}=16\times4=64$

Alternatively, you can write radicals as rational exponents, so that you get

$2\sqrt8\times8\sqrt2=2\tiems8^{1/2}\times8\times2^{1/2}=2^{3/2}8^{3/2}$

Then recalling that $2^3=8$ , you have

$2^{3/2}8^{3/2}=2^{3/2}(2^3)^{3/2}=2^{3/2}2^{9/2}=2^{12/2}=2^6=64$