Using PEMDAS, You know that you have to multiply first so 3*2 is 6. Than you have to add 6+4 which gives you 10... So there for 10 is your answer....
F(x)=1/3-1/21x
0=1/3-1/21x multiply both side by 21
0=7-x
X=7
Answer: width = 72.50 m
Step-by-step explanation:
P = 2l + 2w
425 = 2( 140 ) + 2w
425 - 280 = 2w
145 = 2w
w = 72.50
Solving the quadratic function, it is found that the particle returns to the ground after 7 seconds.
<h3>What is the quadratic function for the particle's height?</h3>
The particle's height after t seconds is modeled by the following equation:
s(t) = -16t² + v(0)t.
In which v(0) is the initial velocity of the particle, which in this problem is of 112 ft/s, hence:
s(t) = -16t² + 112t.
The particle hits the ground when s(t) = 0, hence:
s(t) = 0
-16t² + 112t = 0
-16t(t - 7) = 0.
Hence the non-trivial solution is:
t - 7 = 0 -> t = 7.
The particle returns to the ground after 7 seconds.
More can be learned about quadratic functions at brainly.com/question/24737967
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