Answer:
Width=4, and Length=17
Step-by-step explanation:
first you will make a variable for the width which i will say is x
now make it an equation (3x+5) (x) = 68
then solve 3x^2+5x=68
then 3x^2+5x-68=0
then x=4
then you have to substitute so 3(4)+5= 17 and 4
Answer:
umm...the wording is kinda confusing but im just gonna full send and say its c
Step-by-step explanation:
sry if its wrong lol (it probably is)
Answer:
pretty sure its B
Step-by-step explanation:
Answer:
Length = 208 yards
Width = 54 yards
Step-by-step explanation:
Let the length of the field be "x" yards and the width be "y" yards. Its given that the length is 8 less than quadruple(4 times) the width. So x is 8 less than 4y. We can write this in equation as:
x = 4y - 8 Equation 1
Perimeter of the field is given to be 524 yards. Since, the field is rectangular, its perimeter is calculated as:
Perimeter = 2 (Length + Width)
Using the values, we get:
2(x + y) = 524 Equation 2
Substituting the value of x from Equation 1 into Equation 2, we get:
2(4y - 8 + y) = 524
2(5y - 8) = 524
5y - 8 = 524/2
5y - 8 = 262
5y = 262 + 8
5y = 270
y = 54 yards
Substituting the value of y in Equation 1, we get:
x = 4y - 8 = 4(54) - 8 = 208 yards
Thus, the length of the playing field is 208 yards and its width is 54 yards.
