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34kurt
3 years ago
8

the ratio of girls to boys in a gym class is 1 to 2 if there are 30 students in the class how many girls are in the class?​

Mathematics
2 answers:
UNO [17]3 years ago
8 0

Answer:

The enswer is corect because is the biggest then girls to boys

Step-by-step explanation:

Aleksandr [31]3 years ago
4 0

Answer:

10 Girls

Step-by-step explanation:

This shows that there is twice as many boys in the gym class than girls.

<u>Step 1:  Determine what the ratio relates to the amount</u>

1:2 -> 10:20

10 Girls

20 Boys

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Answer:

  1. Frank grows 535 trees during holiday season
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  3. then dec sold 275
  4. 535 minus 490 which gives a total of 45 trees left
  5. then to find out how many trees he will have next season 650 plus 45 gives 695
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3 years ago
Fraction from greatest to least 1/3, 1/6, 1/2
Vsevolod [243]
1/2 then 1/3 then 1/6
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4 years ago
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Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1
belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

            F(x) = \int\limits^a_b {f(x)} \, dx

By using integration formula

\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c

Given  x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

 \int\limits^6_^-6} (x^{5}  + 8 x^{4}  + 2 x^{2}  + 5 x + 15) )dx

<em>On integration , we get</em>

=   (\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}

F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)

= (\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))

After simplification and cancellation we get

 =  \frac{2 X 8 X (6)^{5} }{5} + \frac{2 X 2 X (6)^3}{3} + 2 X 15 X 6

on calculation , we get

= \frac{124,416}{5} + \frac{864}{3} + 180

On L.C.M  15

= \frac{124,416 X 3 + 864 X 5 + 180 X 15}{15}

= 25 351.2 units²

<u><em>Conclusion</em></u>:-

<em>The area of the region between the graph of the given function and the x-axis = 25,351 units²</em>

6 0
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10 pounds is approximately 4.5 kilograms.
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