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AURORKA [14]
3 years ago
6

Solve the problem and then click on the correct graph. y = |x|

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
8 0

Answer:

Attachment is correct graph.

Step-by-step explanation:

We are given a equation of line y=|x|

It is absolute function which gives always positive value.

It's vertex at (0,0). This function will break at (0,0)

It is linear equality.

f(x)=\left \{ {-x{\ \ \ \ \ \ x

So, function is break at point x=0

Now we make tale of x and y

    x       y  

   -3       3

   -2       2

   -1        1

    0       0

    1        1

    2       2

    3       3

Now we plot the point on graph and join the points to get graph.

Please see the attachment for correct graph.


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Is 1.2 less than or higher than 1.5
Olenka [21]

1.2 is less than 1.5

If you cancel out 1 from both numbers you're left with .2 and .5

Multiply both by 10 and get 2 and 5.

Obviously 2 is less than 5.

4 0
3 years ago
If we used the points (1,8) and (2,16), what is the slope?
Naddik [55]

Answer:  8

Step-by-step explanation:  

See the image

7 0
3 years ago
What is the sum of these expressions: (-3.5t - 4s + 4.5) + (-7.1 - 0.3s + 4.1t)
dmitriy555 [2]
-4.3s + 0.6t - 2.6 is the answer
4 0
3 years ago
You want to enlarge a 4 x 5 inch photo to fit into a 1 inch wide frame
skelet666 [1.2K]

The 4•x by 5•x inner dimensions of the 53 inches outer perimeter picture frame, the 1 inch wide frame and the 4 × 5 inch picture to be enlarged, gives;

a. The outer perimeter equation is presented as follows;

18•x + 8 = 53 inches

b. The scale factor required for the enlargement of the picture is 2.5

<h3>Which method can be used to write the equation and find the scale factor?</h3>

The dimensions of the photo = 4 × 5 inch

Width of the frame = 1 inch

Outer perimeter of the frame = 53 inches

The width of the inside of the picture frame = 4•x

The height of the inside of the picture frame = 5•x

a. The equation for the outer perimeter of the picture frame is therefore;

2 × (4•x + 1 + 1) + 2 × (5•x + 1 + 1) = 53

Which gives;

2 × (4•x + 2) + 2 × (5•x + 2) = 53

8•x + 4 + 10•x + 4 = 53

A simplified equation for the outer perimeter of the picture frame is therefore;

  • 18•x + 8 = 53

b. Solving the above equation, we have;

18•x + 8 = 53

18•x = 53 - 8 = 45

18•x = 45

Therefore;

x = 45 ÷ 18 = 2.5

x = 2.5

The width and height of the picture frame are therefore;

Width = 4•x = 4 × 2.5 = 10

Height = 5•x = 5 × 2.5 = 12.5

Which gives;

Width = 10 inches

Height = 12.5 inches

The enlargement factor, sf, is given by the ratio of a side of the picture frame to a side of the picture as follows;

sf = 12.5/5 = 2.5

  • The factor by which to enlarge the picture frame is 2.5

Learn more about linear scale factors here:

brainly.com/question/19381630

#SPJ1

3 0
2 years ago
I. Daska is situated at a distance of 15 miles from both Gujranwala and Sialkot. A bus travels from Gujranwala to Daska at an av
son4ous [18]

Answer:

The average speed of the entire trip is 8.5 miles per hour.

Step-by-step explanation:

Speed = Total  Distance / Total Time

So we have to find the total distance and the total time taken .

1) From Gujranwala to Daska

speed= 25miles/hour           distance = 15miles

Time taken = distance / speed

                   = 15/25= 0.6 hours

2)  From Daska to Sialkot

speed= 40miles/hour           distance = 15miles

Time taken = distance / speed

                   = 40/15= 2.67 hours

3 ) From  Sialkot to Daska

speed= 30miles/hour           distance = 15miles

Time taken = distance / speed

                   = 30/15= 2 hours

The total distance traveled to three places is = 15+ 15+15= 45miles

The Total time taken is = 0.6+ 2.67+ 2= 5.267=5.3 hours

Speed = Total  Distance / Total Time

Speed= 45/ 5.3

          = 8.49=8.5 miles per hour

The average speed of the entire trip is 8.5 miles per hour.

7 0
3 years ago
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