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Paladinen [302]
3 years ago
5

Solve the equation-2(n+3)=13

Mathematics
2 answers:
bonufazy [111]3 years ago
7 0

Answer:

im thinking n is 6.5 not sure wait not 6.5 its 3.5

Svetradugi [14.3K]3 years ago
5 0

Answer:

Use distributive property

Divide both sides by (-2)

Step-by-step explanation:

First method: Use distributive property:

-2(n + 3) = 13

-2n - 6 = 13    

      -2n = 13 + 6

      -2n = 19

         n = 19/-2

        n = -9.5

2) Divide both sides by (-2)

-2(n +33) = 13

\frac{-2(n + 3)}{2}=\frac{13}{-2}\\\\n + 3 = -6.5\\      n = -6.5 - 3\\      n = -9.5

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sammy [17]

Answer:

y=20

Step-by-step explanation:

25+15=40

2y=40

40/2=20

y=20

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2 years ago
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FIND THE MEDIAN OF THE DATA SET3,35,23,37,45,49,27,48<br> A.35<br> B.34<br> C.30.2<br> D.38
mojhsa [17]

Answer:

A. 35

Step-by-step explanation:

The median of a data set is the middle value when the data values are placed in order of size.

<u>Given data set</u>:

  • {3, 35, 23, 37, 45, 5, 49, 27, 48}

Place the data in <u>order of size</u>:

  • {3, 5, 23, 27, 35, 37, 45, 48, 49}

To find the median, divide the total number of data values (n) by 2.

  • If n/2 is a whole number, the median is halfway between the values in this position and the position above.
  • If n/2 is not a whole number, round it up to find the position of the median.

As there are 9 data values, the median value is:

\implies \dfrac{9}{2}=4.5 \implies \sf 5th\;value

Therefore, the median of the given data set is 35.

4 0
1 year ago
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According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

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For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

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Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

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Step-by-step explanation:

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