Ask question

Ask question

All categories

3 years ago

5

What is the value of X?

1 answer:

Marysya12 [62]3 years ago

6 0

I think it that X equals 9

You might be interested in

Samuel bought a cement mixer for $54,205. The value of the cement mixer depreciated at a constant rate per year. The table shows

Paul [167]

The value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$

Given to us

The value of cement mixer when bought, $P$ = $ 54,205

the value of cement mixer after 1 year, $P_1$ = $ 47,158. 35

the value of cement mixer after 2 year, $P_2$ = $ 41,027. 76

To find out depreciation we can use the formula for depreciation,

$P_n= P(1-r)^n\\where,\\P_n= Value\ of\ asset\ after\ n\ year\\P= Value\ of\ asset\ when\ bought\\r= rate\ of\ depreciation\\n= number\ of\ years$

By putting the value, in the formula we get,

$P_1= P(1-r)^n\\\\47,158.35= 54,205\times (1-r)^1\\\\\dfrac{47,158.35}{54,205} = (1-r)\\\\0.87=1-r\\\\r=0.13$

Therefore, putting the value of $r$ and $P$ in depreciation formula for $t$ years we get,

$P_n= P(1-r)^n$

$f(t) = 54,205(0. 87)^{t}$

Hence, the value of cement mixer after t year is $f(t) = 54,205(0. 87)^{t}$ .

To know more visit:

brainly.com/question/3023490

8 0

2 years ago

There are 144 people in an audience. The ratio of adults to children is 5 to 3. How many are adults?

Igoryamba

Find out how many children there are first. Come on, this is simple fractions/percents/decimals/ratios.

6 0

3 years ago

Read 2 more answers

Solve for c. a (c−b) = d a. c = d - ab / a b. c = ab - d / a c. c = d ab / a d. c = d - ab / a

Nitella [24]

A(c - b) = d
ac - ab = d
ac = d + ab
c = (d + ab)/a

7 0

3 years ago

2. Order the numbers from least to greatest.

kari74 [83]

Answer:

-5, -2, -1, 0, 7

the answer is D

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Write each sequence as a function.

Fiesta28 [93]

Answer: $f(n)=3^{n-1}$

Step-by-step explanation:

Given Recursive formula : $a_{n+1} = 3a_n,$ , $a_1=1$

Then, $a_2=a_{1+1} = 3a_1=3(1)=3$

$a_3=a_{2+1} = 3a_2=3(3)=9$

$a_4=a_{3+1} = 3a_3=3(9)=27$

We can write it as : $f(n)=3^{n-1}$

such that

n $f(n)=3^{n-1}$

1 $f(1)=3^{1-1}=1$

2 $f(2)=3^{2-1}=3^1=3$

3 $f(3)=3^{3-1}=3^2=9$

Hence, the required function: $f(n)=3^{n-1}$

8 0

3 years ago

Read 2 more answers