Answer:
-5/2+-1/2√37≤x≤-5/2+1/2√37
Step-by-step explanation:
Step 1: Find the critical points
-x^2-5x+3=0
For this equation: a=-1, b=-5, c=3
−1x^2+−5x+3=0
x=−b±√b2−4ac/2a
x=−(−5)±√(−5)2−4(−1)(3)/2(-1)
x=5±√37
/−2
x=-5/2+1/2√37
Step 2: Check intervals in between critical points
x≤-5/2+1/2 √37 (Doesn't work in original inequality)
-5/2+-1/2√37≤x≤-5/2+1/2√37 (Works in original inequality)
x≥-5/2+1/2 √37 (Doesn't work in original inequality)
Length of outer boundary =30m
So area of outer boundary =30×30
= 900m²
Length of inner boundary of path=30-1= 29m
Inner area =29×29 =841m²
So area of path is= outer area - inner area
=900- 841
= 59m²
V3+4v2-5v+3v2+12v-15
v3+7v2+7v-15
I answer . The white ones are better trust me, but u have to keep them keep clean!